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Art [367]
3 years ago
10

Write three ordered pairs for direct variation relationship where y= 12 when x= 16

Mathematics
1 answer:
Kruka [31]3 years ago
3 0

Ordered pairs that work for this direct variation are (4, 3), (8, 6) and (12, 9).

In order to find these, we must first find the value of the direct variation coefficient. We can do that using the base equation y = kx and then by plugging in to find k.

y = kx

12 = k(16)

3/4 = k

Now that we have k, we can model the equation as y = 3/4x. We can also find any number of ordered pairs by using the x value and finding the y value. All of the above answers work.

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Factor 24k+36q-12 to identify the equivalent expressions
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Step-by-step explanation:

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3 years ago
The table shows the number of people per day who died from SARS in Singapore at two-week intervals beginning on March 1, 2003.
julia-pushkina [17]

Answer:

Step-by-step explanation:

check attachment for chart

(a) When a data set is given, the area can be calculated using either left Riemann sum (when we use left end points of each interval) or right Riemann sum (when we use right end points of each interval).

Here the intervals are:

|----------------Interval---------------||----left point--||--right point---|

March 1 - March 15 (t0 to t1) : y0 = 0.0079, y1 = 0.0638

March 15 - March 29 (t1 to t2) : y1 = 0.0638, y2 = 0.1944

March 29 - April 12 (t2 to t3) : y2 = 0.1944, y3 = 0.4435

April 12 - April 26 (t3 to t4) : y3 = 0.4435, y4 = 0.5620

April 26 - May 10 (t4 to t5) : y4 = 0.5620, y5 = 0.4630

May 10 - May 24 (t5 to t6) : y5 = 0.4630, y6 = 0.2897

Hence total no. of deaths using left end point:

= y0.\bigtriangleup t + y1.\bigtriangleup t + y2.\bigtriangleup t + y3.\bigtriangleup t + y4.\bigtriangleup t + y5.\bigtriangleup t (\bigtriangleup t = 14 days)
\\\\=(y0 + y1 + y2+ y3 + y4 +y5).\bigtriangleup t
\\\\=(0.0079 + 0.0638 + 0.1944 + 0.4435 + 0.5620 + 0.4630) (14) = 24.2844 \approx 25 deaths (taking next integer value)


And total no. of deaths using right end point:

= y1.\bigtriangleup t + y2.\bigtriangleup t + y3.\bigtriangleup t + y4.\bigtriangleup t + y5.\bigtriangleup t + y6.\bigtriangleup t (\bigtriangleup t = 14 days)
\\\\=(y1 + y2+ y3 + y4 + y5 + y6).\bigtriangleup t
\\\\=(0.0638 + 0.1944 + 0.4435 + 0.5620 + 0.4630 + 0.2897) (14) = 28.2296 \approx 29 deaths (taking next integer value)

b)  If we are given derivative of a function f(t) as a function of time, that is:

\frac{\mathrm{d} }{\mathrm{d} t} (f(t)) = f'(t)


then the function can be evaluated by integrating both the sides. That is:

f(t) = \int f'(t) dt


And by definition we know that integration of a curve gives area under the curve. Hence if we have data for SARS deaths per day (i.e. derivative of total deaths as a function of time) then, if this data is plotted on a curve, area under this curve will give us total no. of deaths during a time period.

8 0
3 years ago
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