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astraxan [27]
3 years ago
15

Y=-4x+2 y = 6.x-8 I don’t understand

Mathematics
1 answer:
Setler [38]3 years ago
3 0

Answer: (1, -2)

Step-by-step explanation:

If you think about that plot from two lines crossed each together, so I have a deal for you, that answer might be (1, -2).

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Are both students equations correct?
larisa86 [58]

Answer:

yes because it is the opposite side

7 0
1 year ago
Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k​
valkas [14]

Answer:

\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k​, the vector projection of B unto a is expressed as proj_ab = \dfrac{b.a}{||a||^2} * a

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k  =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||²  = 130

proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\

<em>Hence the projection of b unto a is expressed as </em>\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\<em></em>

7 0
3 years ago
Can someone help me with factoring by grouping please show step by step
ValentinkaMS [17]
Answer is 3-110x

3 times 1 squared - 11 times 10
1 raised to any power equals 1

calculate the product
3 times 1 -110x

any expression multiplied by one stays the same
3-110x

i hope this helped! thanks!
4 0
3 years ago
Josh rides his bicycle at a rate of 7 miles per hour. At that rate, how long would it take him to ride 28 miles?
Kay [80]

Answer:

4 hours

Step-by-step explanation:

If Josh goes 7mph and does 28 miles that means we have to divide the total miles he goes, by how much he goes in an how that way we can figure out how long it will take him.

28÷7=4

It will take Josh 4 hours

4 0
3 years ago
Read 2 more answers
Helppppppppppppppppp​
maksim [4K]

Answer:

  1. 32.2
  2. -32.61

Step-by-step explanation:

4 0
3 years ago
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