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Kisachek [45]
3 years ago
14

Help me I need help plsss

Mathematics
2 answers:
Simora [160]3 years ago
5 0
1-Growth of 2 inches
2-Debt
3-Elevation at sea level
KatRina [158]3 years ago
3 0
Debt Is A Negative Value
Growth Is A Positive Value
Sea Level Is Zero Or No Value
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Image point B'(4, -8) was transformed using the translation (x-2, y + 3). What were the coordinates of B?
DaniilM [7]

Answer:

B(6 , -11)

Step-by-step explanation:

(x-2 , y+3)  = (4 , -8)

Compare the x & y co ordinates

x - 2 = 4   ; y + 3 = -8

x = 4 +2  ; y = -8 - 3

x = 6      ; y = -11

B(6 , -11)

8 0
3 years ago
I need help, can someone please answer this for me please
blagie [28]

\large \tt \: m =  -  \frac{3}{7}

  • <em>Detailed</em><em> </em><em>solution</em><em> </em><em>is</em><em> </em><em>attached</em><em>!</em><em>!</em><em>~</em>

5 0
2 years ago
Read 2 more answers
Need help asap 8 points
lubasha [3.4K]
Question 13 is 14 x is 14
7 0
3 years ago
Read 2 more answers
If
arlik [135]

Given:

In a right angle triangle θ is an acute angle and \tan\theta =\dfrac{3}{5}.

To find:

The value of \cos \theta.

Solution:

In a right angle triangle,

\tan \theta=\dfrac{Perpendicular}{Base}

We have,

\tan\theta =\dfrac{3}{5}

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

Hypotenuse=\sqrt{Perpendicular^2+base^2}

Hypotenuse=\sqrt{(3x)^2+(5x)^2}

Hypotenuse=\sqrt{9x^2+25x^2}

Hypotenuse=\sqrt{34x^2}

Hypotenuse=x\sqrt{34}

In a right angle triangle,

\cos \theta=\dfrac{Base}{Hypotenuse}

\cos \theta=\dfrac{5x}{x\sqrt{34}}

\cos \theta=\dfrac{5}{\sqrt{34}}

Therefore, the value of \cos \theta is \dfrac{5}{\sqrt{34}}.

8 0
2 years ago
A cylinder with a radius of 12cm and a height of 20cm has the same volume as a cone with a radius of 8cm. What is the height of
ivanzaharov [21]

Answer: 135cm

Step-by-step explanation

Volume of a cylinder = πr²h

Volume of a cone. = 1/3πr²h

The two shapes are both solid shapes.

Since the have same volume, we can then equate the two together and solve for the height of the cone.

Now make H the height and R the radius of the cylinder and h the height and r the radius of the cylinder.

Now equating the two

πR²H = 1/3πr²h

Now substitute for the values now

Multiply through by 3

3πR²H = πr²h

But π is common so it could be obliterated from the equation

3R²H = r²h

3 x 12² x 20 = 8² x h

3 x 144 x 20 = 64 x h

60 x 144 = 64h

8640. = 64h

Therefore

h = 8640/64

= 135cm

8 0
3 years ago
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