Answer:
Explanation:
I’m pretty sure because they need the wait so that they can throw it far and fast
hope this helps mate good day
Answer:
206 mL
Explanation:
In the annexed picture you can see your same question, just in another format.
First we <u>calculate the total moles of CuF₂ that are required in the working solution</u>:
1967 μM ⇒ 1967 / 10⁶ = 1.967 x10⁻³M
1.967 x10⁻³M * 0.275 L = 5.409x10⁻⁴ mol
Now we divide those moles by the concentration of the stock solution, to <u>calculate the volume</u>:
5.409x10⁻⁴ mol ⇒ 5.409x10⁻⁴ * 1000 = 0.5409 mmol
0.5409 mmol ÷ (2.63 mmol/L) = 0.206 L
0.206 L ⇒ 0.206 * 1000 = 206 mL
The rate of reaction between oxygen and copper is higher at high temperature. The rate of reaction between oxygen and copper is lower at room temperature.
at high temperature copper penny will react with oxygen as shown below

The reaction does not occur easily at room temperature
We can say that the reaction between copper and oxygen is an endothermic reaction so the rate of reaction is high at high temperature.
The bond energy of oxygen molecules need energy to react with copper and form copper oxide.
miscible cause the clear blue liquid is a homogeneous mixture
Answer:
B. A rate constant
Explanation:
The mathematical expression of rate law is given below,
Rate = K[A]m[B]n
This rate law show the relationship between the rate of chemical reaction and concentration of reactants.
In given equation [A] and [B] are molar concentration of reactants while K represent rate constant.
The value of K is specific for particular reaction at particular temperature,
m and n are represent exponents and determine experimentally. The value of K is not depend upon the concentrations of reactant but depend upon the surface area and temperature