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irakobra [83]
3 years ago
11

Pls HELP!!!! Why does copper oxide appear on a penny faster when a penny is heated in a flame than when the penny is at room tem

perature EXPLAIN
Chemistry
1 answer:
balu736 [363]3 years ago
5 0

The rate of reaction between oxygen and copper is higher at high temperature. The rate of reaction between oxygen and copper is lower at room temperature.

at high temperature copper penny will react with oxygen as shown below

2Cu(s)+O_{2}-->2CuO

The reaction does not occur easily at room temperature

We can say that the reaction between copper and oxygen is an endothermic reaction so the rate of reaction is high at high temperature.

The bond energy of oxygen molecules need energy to react with copper and form copper oxide.

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A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distill
LekaFEV [45]

Answer:

Whether barium chloride solution was pure

Explanation:

We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:

BaCl_2 (aq)\rightarrow Ba^{2+} (aq) + 2 Cl^- (aq)

Ba^{2+} (aq) + SO_4^{2-} (aq)\rightarrow BaSO_4 (s)

Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

\omega_{Ba^{2+}} = \frac{M_{Ba}}{M_{BaCl_2}} = \frac{137.327 g/mol}{208.23 g/mol\cdot 100\% = 65.95 \%

This means in 10.0 g, we have a total of:

m_{Ba^{2+}} = 10.0 g\cdot 0.6595 = 6.595 g of barium cations.

The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

\omega_{Ba} = \frac{137.327 g/mol}{233.38 g/mol}\cdot 100\% = 58.84 \%

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:

  • if this number is equal to 6.595 g, we have a pure sample of barium chloride;
  • if this number is lower than 6.595 g, this means we have an impure sample of barium chloride, as we were only able to precipitate a fraction of 6.595 g.
3 0
3 years ago
Select the correct answer. if two half-lives have passed since a scientist collected a 1.00-gram sample of u-235, how much u-235
Ugo [173]

Answer:

0.25 g of U-235 isotope will left .

Formula used :

where,

N = amount of U-235 left after n-half lives = ?

= Initial amount of the U-235 = 1.00 g

n = number of half lives passed = 2

0.25 g of U-235 isotope will left .

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What happened to the newt population over many generations
kondor19780726 [428]

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a sickness aka you know what toke them to a better place

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4 years ago
Which of the following terms describes a transfer of energy?
e-lub [12.9K]

Answer:

d

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kinetic energy is transferred into movement.

5 0
3 years ago
Read 2 more answers
PLEASE HELP!! WILL REWARD BRAINLIEST!!!
Irina-Kira [14]

Oxidation number of sulphur in S is 0, in SCl2 is +2, in SO3 is +6, in H2S is - 2, in S2Cl2 is +1, in H2SO4 is +6.

<h3><u>Explanation</u>:</h3>

Oxidation number is the numeric representation of the charge of the particular atom in a compound assuming the compound is 100% ionic in character. This oxidation number is calculated based on the electronegativity of the participating atoms and the valemct of the atoms.

In S, there are no other atoms except sulphur. So its an elemental atom and elemental atoms have oxidation number of 0.

In SCl2, chlorine is more electronegative than sulphur, so chlorine is given - 1 based on its valency and electronegativity. So sulphur will have the oxidation number of +2.

In SO3, oxygen is more electronegative than sulphur, so given - 2 based on its valency and electronegativity. So sulphur will be +6.

In H2S, hydrogen is electropositive than sulphur, so given +1. So the oxidation number of sulphur will be - 2.

In S2Cl2, chlorine is more electronegative than sulphur, so chlorine is given - 1 based on its valency and electronegativity. So sulphur will have the oxidation number of +1.

In H2SO4, hydrogen is electropositive than sulphur, so given +1 and oxygen is more electronegative than sulphur, so given - 2. So oxidation number of sulphur will be +6.

6 0
4 years ago
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