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3 years ago

What is k in the rate law equation?

Chemistry

2 answers:

REY [17]3 years ago

5 0

Answer:

B. A rate constant

Explanation:

The mathematical expression of rate law is given below,

Rate = K[A]m[B]n

This rate law show the relationship between the rate of chemical reaction and concentration of reactants.

In given equation [A] and [B] are molar concentration of reactants while K represent rate constant.

The value of K is specific for particular reaction at particular temperature,

m and n are represent exponents and determine experimentally. The value of K is not depend upon the concentrations of reactant but depend upon the surface area and temperature

Paul [167]3 years ago

5 0

k is a rate constant in the rate law equation

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Is zinc a basic radical or acid radical?

lukranit [14]

Answer:

depends on the element it's reacting with..

Explanation:

if the another element requires less energy to loose electron then zinc will become negatively charged and hence becomes acidic radical..

normally if it is reacting with element with valency 4 and Atomic number less than it(Ti,Si,C) then it will lose electron and gain positive sign and henve becomes basic radical..

6 0

3 years ago

In the wave-mechanical model of the atom, an orbital is defined as

Ne4ueva [31]

Answer:

I think its 2

4 0

4 years ago

If you burn 48.6 g of hydrogen and produce 434 g of water, how much oxygen reacted?

GarryVolchara [31]

Answer:

385.69 g of O₂

Solution:

The Balance Chemical equation for said reaction is as follow;

2 H₂ + O₂ → 2 H₂O

According to Equation,

4.032 g ( 2 mol) H₂ reacts to produce = 36.03 g (2 mol) of H₂O

So,

48.6 g H₂ on reaction will produce = X g of H₂O

Solving for X,

X = (48.6 g × 36.03 g) ÷ 4.032 g

X = 434.29 g of H₂O

It means that the H₂ provided is in Excess. Therefore, the yield of product (H₂O) is being controlled by O₂ (Limiting Reagent).

So, According to Equation,

36.03 g (2 mol) H₂O is produced by = 31.998 g (1 mol) of O₂

So,

434.29 g of H₂O will be produced by = X g of O₂

Solving for X,

X = (434.29 g × 31.998 g) ÷ 36.03 g

X = 385.69 g of O₂

8 0

3 years ago

When a compound containing cesium ions is heated in a Bunsen burner flame, photons with an energy of 4.30 x 10-19 J are emitted.

inessss [21]

<u>Answer:</u> The wavelength of the flame is 462 nm and color of cesium flame is blue.

<u>Explanation:</u>

To calculate the wavelength, we use Planck's equation, which is:

$E=\frac{hc}{\lambda}$

where,

E = Energy of 1 photon = $4.30\times 10^{-19}J$

h = Planck's constant = $6.625\times 10^{-34}J.s$

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength = ?

Putting values in above equation, we get:

$4.30\times 10^{-19}=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{\lambda }\\\\\lambda=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{4.30\times 10^{-19}}=4.62\times 10^{-7}m=462nm$

The range of wavelength of blue light lies in range of 500 nm - 435 nm

The calculated wavelength lies in the above range. So, the color of the cesium flame is 462 nm

Hence, the wavelength of the flame is 462 nm and color of cesium flame is blue.

6 0

3 years ago

A carbene is a highly reactive intermediate in which a carbon atom bears a lone pair and no formal charge: how many hydrogen ato

Colt1911 [192]

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4 0

3 years ago