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lubasha [3.4K]
3 years ago
7

What is k in the rate law equation?

Chemistry
2 answers:
REY [17]3 years ago
5 0

Answer:

B. A rate constant

Explanation:

The mathematical expression of rate law is given below,

Rate = K[A]m[B]n

This rate law show the relationship between the rate of chemical reaction and concentration of reactants.

In given equation [A] and [B] are molar concentration of reactants while K represent rate constant.

The value of K is specific for particular reaction at particular temperature,

m and n are represent exponents and determine experimentally. The value of K is not depend upon the concentrations of reactant but depend upon the surface area and temperature

Paul [167]3 years ago
5 0

k is a rate constant in the rate law equation

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Answer:

Na₂CO₃.2H₂O

Explanation:

For the hydrated compound, let us denote is by Na₂CO₃.xH₂O

The unknown is the value of x which is the amount of water of crystallisation.

Given values:

Starting mass of hydrate i.e Na₂CO₃.xH₂O = 4.31g

Mass after heating (Na₂CO₃) = 3.22g

Mass of the water of crystallisation = (4.31-3.22)g = 1.09g

To determine the integer x, we find the number of moles of the anhydrous Na₂CO₃ and that of the water of crystallisation:

        Number of moles  = \frac{mass }{molar mass }

Molar mass of Na₂CO₃ =[(23x2) + 12 + (16x3)]  = 106gmol⁻¹

Molar mass of H₂O = [(1x2) + (16)] = 18gmol⁻¹

Number of moles of Na₂CO₃ = \frac{3.22}{106} = 0.03mole

Number of moles of H₂O =  \frac{1.09}{18} = 0.06mole

From the obtained number of moles:

                          Na₂CO₃                               H₂O

                           0.03                                    0.06

Simplest

Ratio                  0.03/0.03                         0.03/0.06

                                 1                                      2

Therefore, x = 2    

7 0
4 years ago
A compound can have different chemical and physical properties than
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Explanation:

7 0
3 years ago
Gasoline is a mixture of compounds. A gasoline sample was found to be 2.851% (by mass) octane (C₈H₁₈). 482.6 g of gasoline is co
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Answer:

See below.

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The mass of octane in the sample of gasoline is 0.02851 * 482.6 =  13.759 g of octane.

The balanced equation is:

2C8H18(l)  +  25O2(g) ---->  16CO2(g)  +   18H2O(g)

From the equation, using  atomic masses:

228.29 g of  octane forms 704 g of CO2 and 324.3 g of H2O

So the mass of CO2 formed from the combustion of 13.759 g of octane = (704 * 13.759) / 228.29

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5 0
3 years ago
What volume of 0.0250 m calcium hydroxide is required to neutralize 33.50 ml of 0.0200 m nitric acid?
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For the neutralization reaction, the number of equivalents should be equal. 
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Substituting the known values and with the incorporation of the concept above,
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Hence, the volume of calcium hydroxide needed is approximately equal to 13.4 mL. 
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What evidence indicates that nitric acid (HNO3) is a strong acid?​
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Answer:

The presence of hydrogen ions

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