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gulaghasi [49]
3 years ago
11

Refer to the exhibit. If a hacker on the outside network sends an IP packet with source address 172.30.1.50, destination address

10.0.0.3, source port 23, and destination port 2447, what does the Cisco IOS firewall do with the packet?
Computers and Technology
1 answer:
Luden [163]3 years ago
7 0

Answer:

The packet is dropped

Explanation:

To see why we need to understand the ACL or Access-control list that is a list of permissions that specify which users can access or modify certain things in a system. Because the source IP  doesn't have any parameter and is just a plain IP and packet the Cisco firewall will drop the packet based on the ACL rules, in other words, the Cisco firewall doesn't have any parameter that allows it to verify the permission-level of the sender, therefore, the packet will drop.  

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Complete the method/function so that it converts dash/underscore delimited words into camel casing. The first word within the ou
nata0808 [166]

Answer:

I am writing a Python program. Let me know if you want the program in some other programming language.

def toCamelCase(str):  

   string = str.replace("-", " ").replace("_", " ")  

   string = string.split()

   if len(str) == 0:

       return str

   return string[0] + ''.join(i.capitalize() for i in string[1:])

   

print(toCamelCase("the-stealth-warrior"))

Explanation:

I will explain the code line by line. First line is the definition of  toCamelCase() method with str as an argument. str is basically a string of characters that is to be converted to camel casing in this method.

string = str.replace("-", " ").replace("_", " ") . This statement means the underscore or dash in the entire are removed. After removing the dash and underscore in the string (str), the rest of the string is stored in string variable.  

Next the string = string.split()  uses split() method that splits or breaks the rest of the string in string variable to a list of all words in this variable.

if len(str) == 0 means if the length of the input string is 0 then return str as it is.

If the length of the str string is not 0 then return string[0] + ''.join(i.capitalize() for i in string[1:])  will execute. Lets take an example of a str to show the working of this statement.

Lets say we have str = "the-stealth-warrior". Now after removal of dash in by replace() method the value stored in string variable becomes the stealth warrior. Now the split() method splits this string into list of three words the, stealth, warrior.

Next return string[0] + ''.join(i.capitalize() for i in string[1:])  has string[0] which is the word. Here join() method is used to join all the items or words in the string together.

Now i variable moves through the string from index 1 and onward and keeps capitalizing the first character of the list of every word present in string variable from that index position to the end.  capitalize() method is used for this purpose.

So this means first each first character of each word in the string starting from index position 1 to the end of the string is capitalized and then all the items/words in string are joined by join() method. This means the S of stealth and W of warrior are capitalized and joined as StealthWarrior and added to string[0] = the which returns theStealthWarrior in the output.

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3 years ago
What are some facts about webmasters?
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4 0
3 years ago
Write an assembly language program with a loop and indexed addressing that calculates the sum of all the gaps between successive
PSYCHO15rus [73]

Answer:

Description: Write a MASM 32bit program with a loop and indexed addressing that calculates the sum of all thegaps between successive array elements. The array elements are doublewords, sequenced in nondecreasing order.

;Include Irvine32.inc file used with link library for 32 bit applications

.386

.model flat,stdcall

.stack 4096

ExitProcess proto,dwExitCode:dword

INCLUDE Irvine32.inc

.data

myArray DWORD 0,2,5,9,10

arrSize = ($-myArray)/TYPE myArray

gapArr DWORD arrSize-1 DUP(?)

sum DWORD ?

.code

main PROC

;Call the procedure

call Clrscr

;Initialize ESI pointer

mov esi, 0

mov ecx, arrSize

dec ecx

L1:

mov eax, myArray[esi+4]

sub eax, myArray[esi]

mov gapArr[esi], eax

inc esi

loop L1

;Calculate the sum of gaps between array elements

mov sum, 0

mov esi, 0

mov ecx, arrSize

dec ecx

;  move gapArr[esi] to a temporary register and then add that register value to sum

L2:

mov edx, gapArr[esi]  

add sum, edx

inc esi

loop L2

       INVOKE ExitProcess,0

main ENDP

END main

Explanation:

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Which action does not happen in each iteration of the repeat loop in the
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B. The number of sharks decreases. Explanation: hope it's help i learned about it and you too

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