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den301095 [7]
3 years ago
5

Two pumps are filling a pool. One of them is high power and can fill the pool alone in 2 hours less time than the other can do s

o. Given that, working together, both pumps can fill the pool in 144 minutes, how long, in hours, will it take the powerful pump to fill the pool alone?
Mathematics
1 answer:
Valentin [98]3 years ago
7 0

Answer:

4 hours

Step-by-step explanation:

Let h represent the number of hours the high-power pump requires to fill the pool. Then the number of pools it can fill per hour is 1/h. The low-power pump can fill 1/(h+2) pools in an hour. Together, they can fill 1 pool in 1.2 hours:

1/h + 1/(h+2) = 1/2.4

h+2 +h = h(h+2)/2.4 . . . . . . . multiply by h(h+2)

4.8h +4.8 = h^2 +2h . . . . . . multiply by 2.4

h^2 -2.8h = 4.8 . . . . . . . . . . put in form suitable for completing the square

h^2 -2.8h +1.96 = 6.76 . . . add (2.8/2)^2 = 1.96 to complete the square

h - 1.4 = √6.76 . . . . . . . . . . take the square root of both sides

h = 1.4 +2.6 = 4 . . . . . . . . . hours

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