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Gemiola [76]
3 years ago
7

What is the rate of change between the points (-3, 0) and (-2, -5)?​

Mathematics
1 answer:
Elis [28]3 years ago
3 0

The rate of change is the change in Y over the change in X.

Rate of change =  (-5 - 0) / (-2 - -3)

Rate of change = (-5 ) / (-2+3)

Rate of change = -5 /1

Rate of change = -5

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The lenght of one <br><br> plz answer right show work or describe
Natasha2012 [34]
Since its a right triangle, you can use a² + b² = c²
one of the legs is a and the other leg is b it doesn't matter which one because its addition and works the same way c needs to be the hypotenuse 

so its a² + 48² = 50²
a² + 2304 = 2500
    - 2304    -2304
          a² =  196
      √a² = √196
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7 0
3 years ago
A rectangular sofa cushion is 36 inches by 30 inches by 20 inches. How many cushions can be covered with 38,400 square inches of
elena-s [515]
Is there options ??????????
5 0
3 years ago
Write an exponential function for the value, y, after x years
Anon25 [30]

Step-by-step explanation:

<u>Step 1:  Set x equal to 0 to find the y-int</u>

y = 10000(1 - 0.40) → Not an exponential equation

y=10000(1-0.40)^0 → 10,000 → Works for first test

y = 10000(1-0.60)^0 → 10,000 → Works for first test

y = 10000(1+0.40)^0 → 10,000 → Works for first test

<u>Step 2:  Set x equal to 1</u>

y=10000(1-0.40)^1 → 6,000 → Works for second test

y = 10000(1-0.60)^1 → 4,000 → Does not work for the second test

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Answer:  The answer is Option B

4 0
4 years ago
Write an exponential decay function to model the situation. Compare the average rates of change over the given intervals.
Firlakuza [10]
The exponential decay function could be the model of the situation comparing what I said do not utilize because the user is trying to acoses the points
6 0
3 years ago
You want a snack. One cookie has 130 calories. An orange has 35 calories. What is the ratio of the calories in an orange to the
MrMuchimi
We want the ratio of calories of an orange to a cookie and are told that an orange has 35 calories and a cookie has 130 so:

O:C=35:130

The greatest common factor of 35 and 130 is the product of the shared primes of the numbers prime factorization.

35=5*7 and 130=2*5*13, so the GCF is just 5, so divide each term by 5

O:C=7:26
7 0
3 years ago
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