I’m unsure of what u r asking, I think 6 is ur answer
For the first one it’s x=6.6
And the second one is x=-11
Answer:
y = 6cos(π/2)t
Step-by-step explanation:
Given in the question that,
in a simple harmonic motion in which
at t=0 the amplitude is 6 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at t=0 is 0.
And,
the period is given as 4 sec
We know that model equation of simple harmonic motion is
<h3>y = a. cosb(t + c) + d</h3>
here,
a is amplitude
c is Horizontal shift or phase shift
d is Vertical shift
<h3>Step1</h3><h3>Find b</h3>
Period = 2 π / b
4 = 2π / b
b = 2π/4
b = 1π/2
<h3>Step2</h3><h3>Find shifts</h3>
Horizontal and vertical shifts are 0.
So, c = 0 and d = 0
<h3>Step3</h3><h3>Plug those values in the above in the equation</h3>
y = 6cos π/2 (t + 0) + 0
y = 6cos(π/2)t
Answer:
Yes
Step-by-step explanation:
It is a Pythagorean Triple. A Pythagorean Triple is the sides of a triangle that fit perfectly into the Pythagorean Theorem, which is:
a²+b²=c²
12, 13, and 15 are numbers that you should know off the top of your head so if you see a triangle with 2 of those numbers, you instantly know the 3rd number.
<em>~Stay golden~ :)</em>
What points are A and C? I can see that point B is (-5,3) and point D is (2,1) but what is point A and point C?
