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ZanzabumX [31]
3 years ago
11

"What are the three collinear points? "

Mathematics
2 answers:
Fudgin [204]3 years ago
7 0
Three or more points<span> , , , ..., are said to be </span>collinear<span> if they lie on a single straight line.

LJK   is the answer.</span>
Gnoma [55]3 years ago
6 0

Step-by-step explanation: Points L, J, and K are collinear.

Remember that points are collinear if they lie on the same line.

Since points L, J, and K do all lie on the same line,

we say that these are the three collinear points.

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Assume the random variable x has a binomial distribution with the given probability of obtaining a success. Find the following.
borishaifa [10]

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Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

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In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this question:

n = 14, p = 0.8

P(x>10)

P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 11) = C_{14,11}.(0.8)^{11}.(0.2)^{3} = 0.2501

P(X = 12) = C_{14,12}.(0.8)^{12}.(0.2)^{2} = 0.2501

P(X = 13) = C_{14,13}.(0.8)^{13}.(0.2)^{1} = 0.1539

P(X = 14) = C_{14,14}.(0.8)^{14}.(0.2)^{0} = 0.0440

P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.2501 + 0.2501 + 0.1539 + 0.0440 = 0.6981

So P(x > 10) = 0.6981.

8 0
3 years ago
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