Answer: The required polynomial of lowest degree is 
Step-by-step explanation: We are given to find a polynomial function of lowest degree with real coefficients having zeroes of 2 and -5i.
We know that
if x = a is a zero of a real polynomial function p(x), then (x - a) is a factor of the polynomial p(x).
So, according to the given information, (x - 2) and ( x + 5i) are the factors of the given polynomial.
Also, we know that complex zeroes occur in conjugate pairs, so 5i will also be a zero of the given polynomial.
This implies that (x - 5i) is also a factor of the given polynomial.
Therefore, the polynomial of lowest degree (three) with real coefficients having zeroes of 2 and -5i is given by
Thus, the required polynomial of lowest degree is
Answer:
an = -8 +3(n-1)
an = -11 +3n
f(n) = -11 +3n
Step-by-step explanation:
–8, –5, –2, 1, 4, ...
This is an arithmetic sequence.
We are increasing by 3 each time
-8 +3 = -5
-5+3 = -2
-2 +3 = 1
The common difference is 3
The formula for an arithmetic sequence is
an = a1 +d (n-1)
an = -8 +3(n-1)
an = -8 +3n -3
an = -11 +3n
The nth term is -11 +3n
f(n) = -11 +3n
Hello!
To find the surface area of the given cylinder, we need to use the formula of the surface area of a cylinder.
The formula for the surface area of a cylinder is SA = 2πrh + 2πr².
In this formula, r is the radius and h is the height.
In the given diagram, we see that the height is 6 meters, and the radius 9 meters. With those values, we can substitute them into our formula and solve for the surface area.
In some cases, you are given the diameter. To find the radius, you would need to divide the diameter by two.
SA = 2π(9)(6) + 2π(9)²
SA = 54(2π) + 2(81π)
SA = 108π + 162π
SA = 270π
SA ≈ 848.2 m²
Therefore, the surface area of the given cylinder is choice A, 848.2 m².
