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3 years ago

9

The planner for a company celebration bought 313 balloons. While he was inflating them, 13 of them overinflated and burst. If he

had to place them evenly into 5 rooms, how many balloons were in each room?

1 answer:

KengaRu [80]3 years ago

8 0

He would place 60 balloons in each room. First you subtract 13 from 313 and get 300. Then you divide 300 by 5 which brings you to the answer of 60 balloons per room.

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Factories A, B and C produce computers. Factory A produces 4 times as manycomputers as factory C, and factory B produces 7 times

Elina [12.6K]

Answer:

The probability is $P(A') = 0.485$

Step-by-step explanation:

Let assume that the number of computer produced by factory C is k = 1

So From the question we are told that

The number produced by factory A is 4k = 4

The number produced by factory B is 7k = 7

The probability of defective computers from A is $P(A) = 0.04$

The probability of defective computers from B is $P(B) = 0.02$

The probability of defective computers from C is $P(C) = 0.03$

Now the probability of factory A producing a defective computer out of the 4 computers produced is

$P(a) = 4 * P(A)$

substituting values

$P(a) = 4 * 0.04$

$P(a) = 0.16$

The probability of factory B producing a defective computer out of the 7 computers produced is

$P(b) = 7 * P(B)$

substituting values

$P(b) = 7 * 0.02$

$P(b) = 0.14$

The probability of factory C producing a defective computer out of the 1 computer produced is

$P(c) = 1 * P(C)$

substituting values

$P(c) = 1 * 0.03$

$P(b) = 0.03$

So the probability that the a computer produced from the three factory will be defective is

$P(t) = P(a) + P(b) + P(c)$

substituting values

$P(t) = 0.16 + 0.14 + 0.03$

$P(t) = 0.33$

Now the probability that the defective computer is produced from factory A is

$P(A') = \frac{P(a)}{P(t)}$

$P(A') = \frac{ 0.16}{0.33}$

$P(A') = 0.485$

3 0

3 years ago

A survey among students at a certain university revealed that the number of hours spent studying the week before final exams was

Rainbow [258]

Answer:

$P(25$

And we can find this probability with this difference:

$P(0$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(0$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem'

Let X the random variable that represent the hous spent studying the week before final exams of a population, and for this case we know the distribution for X is given by:

$X \sim N(25,6)$

Where $\mu=25$ and $\sigma=6$

We are interested on this probability

$P(25$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(25$

And we can find this probability with this difference:

$P(0$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(0$

6 0

2 years ago

Lorena has two pieces of ribbons. One piece is 3 meter 14 centimeter long. The other piece is 8 meters 24 centimeters long. How

deff fn [24]

Lorena has
3 meters=300 cm
1st piece=314 cm
8 meters=800 cm
2nd piece=824 cm
together=824+314=1138 cm or 11 meters and 38 cm
1m=100 cm

4 0

3 years ago

P(a number greater than 3 and C

slamgirl [31]

Answer: uhhhh 4

Step-by-step explanation:

3 4 c d

6 0

3 years ago

A $280 suit is marked down by 30%. Find the sale price.<br> The sale price is $

storchak [24]

Answer:

84

Step-by-step explanation:

30% * $280

$\frac{}{100}$

= 84

So, the sale price is $84

3 0

2 years ago

Read 2 more answers