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3 years ago

A) 5x - 30x² = 0 Solve each equation by factoring

Mathematics

1 answer:

Fynjy0 [20]3 years ago

4 0

Answer:

x=0 x = 1/6

Step-by-step explanation:

5x -30x^2 = 0

Factor out the greatest common factor which is 5x

5x(1 -6x) =0

Use the zero product property

5x =0 and 1-6x =0

x =0 -6x = -1

x = -1/-6

x = 1/6

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3 years ago

A certain chain of ice cream stores sells 28 different flavors, and a customer can order a single-, double- , or triple-scoop co

astra-53 [7]

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3 years ago

What are the importance of knowing the theorems on midline, trapezoid and kite

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3 years ago

fathi has $1.10 in his printing account. each sheet of paper he uses reduces his printing account balance by $0.25. Fathi wants

Oksana_A [137]

Answer:

IF THE question is After Fathi prints, what will be the balance in his printing account?

then it is: $1.9

There are 47 pages.

Printing on both sides would divide the number of pages into half.

47/2 = 23.5

2 pages on each side would mean 4 pages on one sheet. Therefore, the number of pages will be further divided by 2.

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There cannot be 11.75 pages so we will round it up to 12 pages.

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3 years ago

Read 2 more answers

Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data

tresset_1 [31]

Based on the information represented by the boxplot ;

Latasha's lowest sale amount = 50

Kayla's median is between 200 and 300

Latasha has a greater spread due to higher IQR value

1.) The Lowest amount of sale made by Latasha in one month

The minimum value is denoted by the starting position of the lower whisker on a boxplot.

Lowest amount of sale made by Latasha = 50

2.) 50% of sales made by Kayla :

50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

50% of sales made by Kayla is between 200 and 300

With median sale value being 250

3.) Spread of the middle 50% of sales :

The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

IQR = Upper Quartile (Q3) - Lower quartile(Q1)

For Latasha :

Q3 = 450 (Endpoint of the box)
Q1 = 150 (starting point of the box)

IQR = 450 - 150 = 300

For Kayla :

Q3 = 375 (Endpoint of the box)
Q1 = 100 (starting point of the box)
IQR = 375 - 100 = 275

Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

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2 years ago