This is the number of combinations of 7 in 10 which is the same as number of combinations of 3 in 10:
10C3 = 10*9*8 / 3*2*1
= 120
Hey there
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The correct answer is:
f(x+5)=(x+5)^2+3(x+5)-10
f(x+5)=x^2+10x+25+3x+15-10
f(x+5)=x^2+13x+30 and f(x+5)=x^2+kx+30 so
k=13
Now factor x^2+13x+30
Find j and k such that jk=ac=30 and j+k+b=13 so j and k are 10 and 3 so
(x+3)(x+10)
So the two zeros occur when x=-3 and -10 the smallest of which is:
x=-10
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Hope this helps you
Answer: 31
Step-by-step explanation: 8+8+15=31
This is a a reflective property because it is an if then statement.
X = 4 y = - 3
Substitute x for 4 and y for - 3
<u>x² - 4y
</u> 2
<u>4² - 4 *(- 3</u><u>)
</u> 2
<u>16 - ( - 12 )</u>
2
<u>16 + 12</u>
2
<u>28</u> = 14
2
Solution: 14