Answer:
the numerical value of the correlation between percent of classes attended and grade index is r = 0.4
Step-by-step explanation:
Given the data in the question;
we know that;
the coefficient of determination is r²
while the correlation coefficient is defined as r = √(r²)
The coefficient of determination tells us the percentage of the variation in y by the corresponding variation in x.
Now, given that class attendance explained 16% of the variation in grade index among the students.
so
coefficient of determination is r² = 16%
The correlation coefficient between percent of classes attended and grade index will be;
r = √(r²)
r = √( 16% )
r = √( 0.16 )
r = 0.4
Therefore, the numerical value of the correlation between percent of classes attended and grade index is r = 0.4
F(3k)=3k +7 Equals 9k+7. So 9k+7 would be the Answer.
Write i in trigonometric form. Since |i| = 1 and arg(i) = π/2, we have
i = exp(i π/2) = cos(π/2) + i sin(π/2)
By DeMoivre's theorem,
i² = exp(i π/2)² = exp(i π) = cos(π) + i sin(π)
and it follows that i² = -1 since cos(π) = -1 and sin(π) = 0.
I’ll try my best but sorry if I can’t help a lot I’m not the best at math
Answer: C
Step-by-step explanation:
<u>Given:</u>
Sample size (n) = 50
x = 12
Confidence level = 90%
α = 1 − 0.90 = 0.10
α/2 = 0.05
(from standard normal table)
90% Confidence interval is,
Therefore, 90% confidence interval for the true proportion of sophomores who favour the adoption of uniforms is C
