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Blababa [14]
3 years ago
14

How many permutations exist of the letters a, b, c, d taken three at a time? 24 12 4

Mathematics
2 answers:
sweet [91]3 years ago
6 0

Answer:

Option A. 24

Step-by-step explanation:

There are four letters a, b, c, d and we have to tell the permutations made when taken 3 at a time.

This phenomenon exist = ^{4}P_{3} = \frac{4!}{(4-3)!}

=  \frac{4!}{1!} = 4! = 4 × 3 × 2× 1 = 24

Therefore, option (A) 24 are the permutations exist.

Travka [436]3 years ago
4 0
The correct answer is 24

You have to apply factorials here and formulas. You have 4 letters which means that your n=4, and you have 3 objects at a time which, means that you have 4 different groups of combinations with 6 permutations in each due to the 3! factorial. 6 x 4 is 24.
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