Question

How many permutations exist of the letters a, b, c, d taken three at a time? 24 12 4

Answer 1

Answer:

Option A. 24

Step-by-step explanation:

There are four letters a, b, c, d and we have to tell the permutations made when taken 3 at a time.

This phenomenon exist = $^{4}P_{3}$ = $\frac{4!}{(4-3)!}$

=  $\frac{4!}{1!}$ = 4! = 4 × 3 × 2× 1 = 24

Therefore, option (A) 24 are the permutations exist.

Answer 2

The correct answer is 24

You have to apply factorials here and formulas. You have 4 letters which means that your n=4, and you have 3 objects at a time which, means that you have 4 different groups of combinations with 6 permutations in each due to the 3! factorial. 6 x 4 is 24.