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3 years ago

How should I draw out the sons and daughters of liberty in a British point of view in a editorial cartoon style?

Social Studies

1 answer:

Tanzania [10]3 years ago

6 0

Answer:

The Sons of Liberty and the Daughters of Liberty were two groups who led the resistance to the Stamp Act.

Explanation:

Political cartoons are known as Editorial cartoons express political issues and policies in a humorous way in form of art. It may also include satire in its art exaggerating controversies and issues at times.

The sons of liberty and the daughters of liberty were formed in American British colonies during the American revolution. Their main purpose was to protest against the unjust taxation system of the British government on the colonies.

The Daughters of Liberty used to participate in spinning bees and help in producing homespun cloth for colonists to wear instead of British textiles. One can draw a cartoon of women depicted as 'Daughters of Liberty' spinning bees.

The Sons of Liberty were merchants, shopkeepers who fought against the taxation system by the British government. Their cartoon may have boys protesting and raising slogan against taxes.

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What was Ben Franklin known for in the colonies and what movement was he a part of?

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Answer:

In 1776, he was part of the five-member committee that helped draft the Declaration of Independence, in which the 13 American colonies declared their freedom from British rule. That same year, Congress sent Franklin to France to enlist that nation's help with the Revolutionary War

Explanation:

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3 years ago

____________ is defined as a cluster of characteristics that are associated with all members of a specific social group, often i

pashok25 [27]

Answer: Stereotype

Explanation:

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3 years ago

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3 years ago

Read 2 more answers

A basketball is dropped from the edge of a cliff at the same time that second basketball is thrown upward from the ground. When

pentagon [3]

Answer:

The collision occurs at a height of 1/3 of the total height of cliff.

Explanation:

The situation is represented in the attached figure:

For the stone dropped from top of cliff we have

Initial velocity of drop= 0 m/s.

Now the time at which it attains a velocity of 2v is obtained from first equation of kinematics as

$v_{f}=u_{i}+gt\\\\2v=0+gt\\\\\therefore t=\frac{2v}{g}$

Thus the distance it covers in this time can be calculated using third equation of kinematics as

$v_{f}^{2}=v_{i}^{2}+2gh\\\\(2v)^{2}=2gh_{1}\\\\\therefore h_{1}=\frac{2v^{2}}{g}$

For the stone thrown upwards the velocity at collision is give as 'v' thus the velocity at which it is thrown upwards can be calculated by first equation of kinematics as

$v=v_{i}-gt\\\\\therefore v_{i}=v+gt\\\\v_{i}=v+g\times \frac{2v}{g}\\\\\therefore v_{i}=3v$

The height over which it changes it's velocity from '3v' to 'v' can be again obtained from third equation of kinematics as

$v^{2}=(3v)^{2}-2gh_{2}\\\\v^{2}=9v^{2}-2gh_{2}\\\\\therefore h_{2}=\frac{4v^{2}}{g}$

$\therefore h_{2}=2h_{1}$

Thus the collision occurs at at a fraction of 1/3 of height.

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