The product of - 73 and a number.

Mathematics

2 answers:

Olenka [21]2 years ago

5 0

Answer:

The answer is -73x.

Ede4ka [16]2 years ago

3 0

Answer:

-73x

Step-by-step explanation:

Since you dont know what the number is you use a variable in place of it.

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ILL BRAINLIEST YOU PLEASE HELP ME

Aleksandr-060686 [28]

Answer:

x = 71/5 (as an improper fraction)

x = 14 1/5 (as a proper fraction

x = 14.2 (as a decimal)

Step-by-step explanation:

It's a rectangle so the diagonals are equal

7x - 9 = 2x + 62

Subtract 2x from both sides

5x - 9 = 62

Add 9 to both sides

5x = 71

Divide both sides by 5

x = 71/5 (as an improper fraction)

x = 14 1/5 (as a proper fraction

x = 14.2 (as a decimal)

8 0

2 years ago

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PLEASE HELP ASAP, FIRST PERSON ANSWERS WILL GIVE BRAINLIST WILL GIVE 20 PTS

kakasveta [241]

C is the correct answer because in a title, you always want to capitalize the bigger and more describing words.
Hope this helped!

6 0

3 years ago

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Express p in terms of q if

Irina-Kira [14]

$p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)$

$q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}$