13 scaled down by 1/5
= 13 ÷ 1/5
= 13 × 5/1
= 65.
There would be 30 adults because, if you were to take 3/10 and multiple both numbers until the denominator was 100 (10 X 10 = 100, 10 X 3 = 30). Resulting in your numerator to be 30. Therefore there were 30 adults.
lx-1 l ≤ 13
There are 2 solutions:
x-1 ≤ 13
and
x-1 ≥ -13
Solve each one
x-1 ≤ 13
add 1 to both sides of the equation
x-1+1≤ 13+1
x ≤ 14
x-1 ≥ -13
Add 1 to both sides:
x-1+1 ≥-13+1
x ≥ -12
-12 ≤ x ≤ 14
I think it’s B but I dint really know