A factor that is common to all terms of an expression or to two or more expressions

Mathematics

1 answer:

avanturin [10]3 years ago

4 0

Answer:

el1

<h3>elnumero e s 1</h3>

You might be interested in

Need answer ASAP <br> *MARKING BRAINLIEST

NikAS [45]

Answer:

an = 4n +5

Step-by-step explanation:

First we need to find a common difference

d = a2-a1 = 13-9 = 4

The formula for an

an =a1+d(n-1)

an = 9 + 4(n-1)

Distributing

an = 9+4n-4

Combine like terms

an = 4n +5

8 0

3 years ago

Find the product.

4vir4ik [10]

Answer :

$6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}$

Step-by-step explanation :

To find the product of

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

$= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)$

we now apply the law of indices

${a}^{m} \times {a}^{n} = {a}^{m+n}$

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

$= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}$