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3 years ago

The prime factorization of 25 is .

Mathematics

1 answer:

Setler [38]3 years ago

4 0

Answer:

$\pi \: the \: prime \: factorization \: of \: 25 \: is \: 5 \: x \: 5 \:$

Step-by-step explanation:

$\pi\pi \: hope \: it \: works \: out \: \pi\pi\pi$

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What 5x23p9x2 and what is the common number?

loris [4]

Hi There! :)

What 5x23p9x2 and what is the common number?

5×23=115
115×9=1035
1035×2=2070

Therefore 2070 is the answer

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3 years ago

The area of a square garden is 50 m². How long is the diagonal? 100 m mc028-1.jpg m 25 m 10 m

SCORPION-xisa [38]

A=s^2 50=S^2 s= sqrt50 s=7.071 ms a^2+a^2=c^2 50+50=c^2 100=c^2 c= sqrt100 c=10ms So the answer would be 10 hope this helped

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3 years ago

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The figure below shows a shaded region and a non-shaded region. Angles in the figure that appear to be right angles are right an

polet [3.4K]

Answer:

Step-by-step explanatioihhin:

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3 years ago

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PLEASE SHOW WORK

CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

$V = \dfrac{\pi}{3}r^2h$

Taking the derivative of V with respect to time, we get

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)$

$\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)$

Since r is always equal to h, we can set

$\dfrac{dr}{dt} = \dfrac{dh}{dt}$

so that our expression for dV/dt becomes

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\left(3r^2\dfrac{dh}{dt}\right)$

$\:\:\:\:\:\:\:= \pi r^2\dfrac{dh}{dt}$

Solving for dh/dt, we get

$\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}$

$\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})$

$\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}$

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3 years ago

Divide the combinations. 60C3 / 15C3

Mariulka [41]

I hope you know what '!' means
2!=2
3!=6
4!=24
basicalkly times every natural number including and before that number

nCr= $\frac{n!}{r!(n-r)!}$
so
$\frac{60C3}{15C3}$ =
$\frac{ \frac{60!}{3!(60-3)!} }{ \frac{15!}{3!(15-3)!} }$ =
$( \frac{60!}{3!(60-3)!})(\frac{3!(15-3)!}{15!})$ =
$( \frac{60!}{3!(57)!})(\frac{3!(12)!}{15!})$ =
$\frac{(60!)(3!)(12!)}{(3!)(57!)(15!)}$ =
$\frac{(60!)(12!)}{(57!)(15!)}$ =
$\frac{(60!)}{(57!)(15)(14)(13)}$ =
$\frac{(60)(59)(58)}{(15)(14)(13)}$ =
$\frac{(30)(59)(58)}{(15)(7)(13)}$ =
$\frac{(6)(59)(58)}{(3)(7)(13)}$ =
$\frac{6844}{91}$

4 0

3 years ago

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