Question

Find the distance between the two points shown in the coordinate plane below to the nearest hundredth.

Answer 1

Answer:

7.81

Step-by-step explanation:

Given points (-2,-2)  and (3, 4)

To find distance between points we apply distance formula

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

(x1,y1) is (-2,-2)  and (x2,y2) is (3,4)

Plug in the values in the formula

$D = \sqrt{(3-(-2))^2+(4-(-2))^2}$

$D = \sqrt{(5)^2+(6)^2}$

$D = \sqrt{25+36}$

$D = \sqrt{61}$

D= 7.810249676

Round to nearest hundredth

So distance = 7.81