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3 years ago

Math - Ratios

Mathematics

1 answer:

Llana [10]3 years ago

8 0

The answer is 9 : 5
36:20
18:10
9:5

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The table displays the amount of time, in minutes, Jordan rode his bike for five days. How many total hours did Jordan ride his

Zinaida [17]

Answer:98.9276

Step-by-step explanation:

The table displays the amount of time, in minutes, Jordan rode his bike for five days. How many total hours did Jordan ride his bike in the five days? DayTime (minutes)11 4545 22 109109 33 5151 44 121121 55 3838 Jordan rode his bike total hours in the five days.

8 0

2 years ago

Change the repeating decimal to a fraction:<br> 0.376376376...

taurus [48]

Answer:

Answer is 3/4

Step-by-step explanation:

3 0

2 years ago

12x⁴y²divided by 3x³y to the 5 th power....Please help me out....

ki77a [65]

To divide the expression we proceed as follows:
12x⁴y²÷3x³y⁵
=12x⁴y²/3x³y⁵
=(12÷3)×(x⁴÷x³)×(y²÷y⁵)
when you divide number with the same base, you subtract the numerators:
=4×(x⁴⁻³)×(y²⁻⁵)
simplifying this we get
=4xy⁻³
Answer: 4xy⁻³

5 0

3 years ago

Distributive/ like terms<br> Pre-Alegbra<br> Overdue!!

il63 [147K]

HI!

Here are the answers:

1) x=39/7 or 5.57

2) x=1

3) y=42

4) c=9

I hope this helps!

Feel free to mark brainliest!

If you have any other questions, don't hesitate to let me know!

3 0

2 years ago

Read 2 more answers

Let c be the curve of intersection of the parabolic cylinder x2 = 2y, and the surface 3z = xy. find the exact length of c from t

Mandarinka [93]

Parameterize the intersection by setting $x(t)=t$ , so that

$x^2=2y\iff y=\dfrac{x^2}2\implies y(t)=\dfrac{t^2}2$
$3z=xy\iff z=\dfrac{xy}3\implies z(t)=\dfrac{t^3}6$

The length of the path $C$ is then given by the line integral along $C$ ,

$\displaystyle\int_C\mathrm dS$

where $\mathrm dS=\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt$ . We have

$\dfrac{\mathrm dx}{\mathrm dt}=1$
$\dfrac{\mathrm dy}{\mathrm dt}=t$
$\dfrac{\mathrm dz}{\mathrm dt}=\dfrac{t^2}2$

and so the line integral is

$\displaystyle\int_{t=0}^{t=2}\sqrt{1^2+t^2+\dfrac{t^4}4}\,\mathrm dt$

This result is fortuitous, since we can write

$1+t^2+\dfrac{t^4}4=\dfrac14(t^4+4t^2+4)=\dfrac{(t^2+2)^2}4=\left(\dfrac{t^2+2}2\right)^2$

and so the integral reduces to

$\displaystyle\int_{t=0}^{t=2}\frac{t^2+2}2\,\mathrm dt=\dfrac{10}3$

3 0

3 years ago