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2 years ago

Help help help help

Mathematics

2 answers:

abruzzese [7]2 years ago

4 0

$\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\green{W}\red{E}\purple{R:-}}}$

Here we've been provided with the information given that radius (r) = 3.

And we have to find the circumference (c) of circle. And we have been provided with the formula i.e C = 2πr.

Placing (π = 3) in the above equation,

$:\implies\tt{c = 2\pi r}$

$:\implies\tt{c = 2 \times 3 \times 3}$

$:\implies\tt{c = 6 \times 3}$

$:\implies\tt{c = 18}$

The circumference of circle is 18cm.

Crank2 years ago

3 0

Answer:

C = 18

Step-by-step explanation:

Put the numbers in place of their symbols and do the arithmetic. The diagram is showing you r = 3.

C = 2πr

C = 2(3)(3) . . . . . using 3 for π, as directed

C = 18

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6 0

3 years ago

15s-100=350 Can someone answer please.

seraphim [82]

Answer:

15s=350+100

15s=450

s=450/15

s=30

Hope it helps:-)

3 0

3 years ago

Find the value of the variable.

Zielflug [23.3K]

Answer:

x = 8, y = $8\sqrt{2}$

Step-by-step explanation:

$a^2+b^2=c^2$

$8^2+8^2=c^2$ Both 8 and x sides are congruent so they're equal.

$64+64=c^2$ Add 64 + 64.

$c^2=128$ Square root 128

$c^2=8\sqrt{2}$

Final answers: x = 8, y = $8\sqrt{2}$

3 0

3 years ago

Read 2 more answers

Anyone know the answer?

Zepler [3.9K]

If you look from the points at angle 73, to 42, to 131, to z, the shape makes a quadrilateral.
Since the total of the interior angles in a quadrilateral add up to 360 you make an equation:

360 = 131 + 73 + 42 + 7 + x
Re-arrange the equation to get the x alone, by subtracting:
360 - 131 - 73 - 42 = x
114 = x

So x = 114 degrees<span />

7 0

3 years ago

The scores on the LSAT are approximately normal with mean of 150.7 and standard deviation of 10.2. (Source: www.lsat.org.) Queen

faltersainse [42]

Answer:

$a=150.7 -0.385*10.2=146.773$

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Solution to the problem

Let X the random variable that represent the scores on the LSAT of a population, and for this case we know the distribution for X is given by:

$X \sim N(150.7,10.2)$

Where $\mu=150.7$ and $\sigma=10.2$

We want to find a value a, such that we satisfy this condition:

$P(X>a)=0.65$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.35 of the area on the left and 0.65 of the area on the right it's z=-0.385. On this case P(Z<-0.385)=0.35 and P(Z>-0.385)=0.65

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$Z=-0.385$

And if we solve for a we got

$a=150.7 -0.385*10.2=146.773$

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.

5 0

3 years ago

Read 2 more answers