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3 years ago

How much of the circle is shaded? Write your answer as a fraction in simplest form

Mathematics

2 answers:

e-lub [12.9K]3 years ago

8 0

Answer:

5/21

Step-by-step explanation:

add the two unshaded portions and subtract that from 21/21, or 1 whole

3/7 = 9/21

1/3 = 7/21

sum of unshaded portions is equal to 16/21

21/21 - 16/21 = 5/21

antoniya [11.8K]3 years ago

3 0

Answer:

I think it may be 2/4 or 4/10

not to sure....I forgot how to do this but yeah.. don't go with my answers to be safe.

Step-by-step explanation:

3+1=4

3-1=2

7+3=10

3-7=4

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Use the identity (x+y)(x^2−xy+y^2)=x^3+y^3 to find the sum of two numbers if the product of the numbers is 28, the sum of the sq

lara31 [8.8K]

Step-by-step explanation:

We have xy = 28, x² + y² = 65 and x³ + y³ = 407.

Since (x + y)(x² - xy + y²) = x³ + y³,

x + y = (x³ + y³)/(x² + y² - xy)

= (407) / [(65) - (28)]

= 407 / 37

= 11.

Hence the sum of the numbers is 11.

4 0

2 years ago

Read 2 more answers

A coin is flipped 40 times and it lands on head 16 timed based on the experimental probability how many heads would you protect

crimeas [40]

24 abcdefghijklmnopqrstuvwxyz

4 0

3 years ago

What is 42 inches to 9 feet is a fraction in simplest form

hodyreva [135]

9 times 12 is 108. so 42/108=21/54

4 0

3 years ago

What is the equation of the line that passes through the point (7,2) and has a slope of 1?

Tema [17]

Answer:

x-y=5

Step-by-step explanation:

If a line has a slope of 1, its function can be write as x-y=c

insert point (7,2),t then we can find out the constant c=5, so the equation of this line is x-y=5

6 0

2 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

3 years ago