Mike ($3.75): x
Friends ($3.75): 3x
Mike + Friends ≤ 25
3.75(x) + 3.75(3x) ≤ 25
3.75x + 11.25x ≤ 25
15x ≤ 25
≤
x ≤ 1
Answer: they can rent the paddleboards for 1 hour 40 minutes
3a+ 6 = 15, 3a = 9, a+ 2= 5, 1/3a =1
1 answer:
Given parameters:
Find if any of the equations are the equivalent;
3a+ 6 = 15
3a = 9
a+ 2= 5
=1
To find which of the equations are equivalent to one another, let us solve them first. The ones with the same solution are definitely equivalent.
(i) 3a+ 6 = 15
3a = 15 - 6
3a = 9
a = 3
(II) 3a = 9
a = 3
(III) a+ 2= 5
a = 5-2
a = 3
(IV) =1
1 = 3a
a =
We clearly see that the first three equations are equivalent.
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Answer:
7
Step-by-step explanation:
To solve this you just have to replace the letters with the corresponding numbers. 5/5 = 1 and 1+6 = 7
So your answer is 7!
Answer:
When we have a quadratic equation:
a*x^2 + b*x + c = 0
There is something called the determinant, and this is:
D = b^2 - 4*a*c
If D < 0, then the we will have complex solutions.
In our case, we have
5*x^2 - 10*x + c = 0
Then the determinant is:
D = (-10)^2 - 4*5*c = 100 - 4*5*c
And we want this to be smaller than zero, then let's find the value of c such that the determinant is exactly zero:
D = 0 = 100 - 4*5*c
4*5*c = 100
20*c = 100
c = 100/20 = 5
As c is multiplicating the negative term in the equation, if c increases, then we will have that D < 0.
This means that c must be larger than 5 if we want to have complex solutions,
c > 5.
I can not represent this in your number line, but this would be represented with a white dot in the five, that extends infinitely to the right, something like the image below:
