Atomic radius of magnesium

After creating a Beer's Law plot using standard solutions of Q, you determined the slope of Beer's Law to be 0.598 M-1. Your unk

Mashutka [201]

Answer:

$C=0.247~M$

Explanation:

We have to start this question with Beer's Law, $A=E*b*C*$ . On this equation we will have:

A=Absorbance

E=Molar absorption coefficient

b= Optical path

C=Concentration

So, the question is: what values of this equation we know?. If we check the question we have the absorbance value "0.148" additionally we have the slope of the plot, this slope is the molar absorption coefficient, therefore E=0.598 M-1, finally we have also the optical path. The optical path is 1 cm for all devices, so b=1 cm. With all these values we can calculate the concentration "C".

$C=\frac{A}{b*E}$

$C=\frac{0.148}{1*0.598}$

$C=0.247~M$

So, we will have a concentration of 0.247 M

I hope it helps!

4 0

3 years ago

Identify the oxidizing agent in the reaction: Sn(s) + 2H+(aq) → Sn2+(aq) + H2(g) Sn2+ H2 H+ Sn

MrRa [10]

Answer:

H⁺(aq)

Explanation:

Let's consider the following redox reaction.

Sn(s) + 2 H⁺(aq) → Sn²⁺(aq) + H₂(g)

We can identify both half-reactions.

Oxidation: Sn(s) → Sn²⁺(aq) + 2 e⁻

Reduction: 2 H⁺(aq) + 2 e⁻ → H₂(g)

Sn(s) undergoes oxidation so it is the reducing agent, while H⁺(aq) undergoes reduction so it is the oxidizing agent.

8 0

3 years ago

Pls help...

rjkz [21]

Answer: c

Explanation:

4 0

3 years ago

Read 2 more answers

A 3.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of

andrew-mc [135]

Answer: The molecular formula for the given organic compound X is $C_6H_{8}O_7$

Explanation:

We are given:

Mass of $CO_2=4.13g$

Mass of $H_2O=1.13g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 4.13 g of carbon dioxide, = $\frac{12}{44}\times 4.13=1.13g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.13 g of water, $\frac{2}{18}\times 1.13=0.125g$ of hydrogen will be contained.

Mass of oxygen in the compound = (3.00) - (1.13+ 0.125) = 1.75 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.13g}{12g/mole}=0.094moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.125g}{1g/mole}=0.125moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.75g}{16g/mole}=0.109moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles

For Carbon = $\frac{0.094}{0.094}=1$

For Hydrogen = $\frac{0.125}{0.094}=1.33$

For Oxygen = $\frac{0.109}{0.094}=1.16$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1: 1.33: 1.16

Converting them into whole number ratios by multiplying by 6:

The ratio of C : H : O = 6: 8: 7

Hence, the empirical formula for the given compound is $C_6H_8O_7$

Empirical mass = $6\times 12+8\times 1+7\times 16=192g$

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

Putting values in above equation, we get:

$n=\frac{192g/mol}{192g/mol}=1$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_6H_8O_7\times 1=C_6H_{8}O_7$

Thus molecular formula for the given organic compound X is $C_6H_{8}O_7$

7 0

3 years ago

Để trung hoà 20ml dung dịch HCl 0.1M cần 10ml dung dịch NaOH nồng độ x mol/l . Giá trị của x là

elena55 [62]

The question is: To neutralize 20ml of 0.1M HCl solution, 10ml of NaOH solution of concentration x mol/l is required. What is the value of x?

Answer: The value of x is 0.2 M.

Explanation:

Given: $V_{1}$ = 20 mL, $M_{1}$ = 0.1 M

$V_{2}$ = 10 mL, $M_{2}$ = x

Formula used is as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times 20 mL = x \times 10 mL\\x = 0.2 M$

Thus, we can conclude that the value of x is 0.2 M.

6 0

3 years ago