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son4ous [18]
3 years ago
7

After creating a Beer's Law plot using standard solutions of Q, you determined the slope of Beer's Law to be 0.598 M-1. Your unk

nown solution of Q tested had an absorbance of 0.148. Determine the concentration (in molarity) of the unknown solution.
Chemistry
1 answer:
Mashutka [201]3 years ago
4 0

Answer:

C=0.247~M

Explanation:

We have to start this question with <u>Beer's Law</u>, A=E*b*C*. On this equation we will have:

<u>A=Absorbance</u>

<u>E=Molar absorption coefficient</u>

<u>b= Optical path</u>

<u>C=Concentration</u>

So, the question is: <u>what values of this equation we know?</u>. If we check the question we have the <u>absorbance value "0.148"</u> additionally we have the slope of the plot, this <u>slope is the molar absorption coefficient</u>, therefore <u>E=0.598 M-1</u>, finally we have also the optical path. <u>The optical path is 1 cm</u> for all devices, so <u>b=1 cm</u>. With all these values we can calculate the concentration "C".

C=\frac{A}{b*E}

C=\frac{0.148}{1*0.598}

C=0.247~M

So, we will have a <u>concentration of 0.247 M</u>

I hope it helps!

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solniwko [45]

Answer:

A. To study the chemical composition of the surface of a planet

Explanation:

Strictly speaking, a spectrometer is any instrument used to view and analyze a range (or a spectrum) of a given characteristic for a substance (for example, a range of mass-to-charge values as in mass spectrometry), or a range of wavelengths as in absorption spectrometry like nuclear magnetic radiation spectroscopy

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6 0
2 years ago
Read 2 more answers
What is the pressure of a mixture of 0.200 g of H2, 1.00 g of N2 , and 0.820 g of Ar in a container with a volume of 2.00 L at 2
alexdok [17]

Answer:

P(mixture) = 1.92 atm

Explanation:

Given data:

Mass of H₂ = 0.200 g

Mass of N₂ = 1.00 g

Mass of Ar = 0.820 g

Volume = 2 L

Temperature = 20°C

Pressure of mixture = ?

Solution:

Pressure of hydrogen:

Number of moles of hydrogen = mass / molar mass

Number of moles of hydrogen = 0.200 g / 2 g/mol

Number of moles of hydrogen = 0.1 mol

P = nRT / V

P = 0.1 mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 293 K / 2L

p = 2.41 atm. L /2 L

P = 1.2 atm

Pressure of nitrogen:

Number of moles of nitrogen = mass / molar mass

Number of moles of nitrogen = 1 g / 28 g/mol

Number of moles of nitrogen = 0.04 mol

P = nRT / V

P = 0.04 mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 293 K / 2L

p = 0.96 atm. L /2 L

P = 0.48 atm

Pressure of argon:

Number of moles of argon = mass / molar mass

Number of moles of argon = 0.820 g / 40 g/mol

Number of moles of argon = 0.02 mol

P = nRT / V

P = 0.02 mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 293 K / 2L

p = 0.48 atm. L /2 L

P = 0.24 atm

Total pressure of mixture:

P(mixture)  = pressure of hydrogen + pressure of nitrogen + pressure of argon

P(mixture)  = 1.2 atm + 0.48 atm + 0.24 atm

P(mixture) = 1.92 atm

5 0
4 years ago
Which area should have the lowest temperatures?<br><br> A. 1<br><br> B.2 <br><br> C.3 <br><br> D.4
pochemuha

Answer:

A. 1

Explanation:

The higher you get in the atmosphere the cooler the temperature will be. The reason it's actually colder is because, as you go up in the atmosphere, the Earth's atmosphere feels less pressure the higher up you go. So as the gas in the atmosphere rises it feels less pressure, which makes it expand.

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7 0
3 years ago
What would happen if there was no sodium potassium pump?
vladimir1956 [14]
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5 0
3 years ago
Consider the above unbalanced equation. What volume of CO2 is produced at 270. mm Hg and 38.5°C when 0.820 g of C4H8 reacts with
irinina [24]

Answer:

The volume of CO2 is 4.20 L

Explanation:

Step 1: Data given

Pressure = 270 mm Hg =  260 /760 = 0.355263 atm

Temperature : 38.5 °C = 311.65 K

Mass of C4H8 = 0.820 grams

Step 2: The balanced equation

C4H8 + 6O2 → 4CO2 + 4H2O

Step 3: Calculate moles C4H8

Moles C4H8 = mass C4H8 / molar mass C4H8

Moles C4H8 = 0.820 grams / 56.11 g/mol

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Step 4: Caalculate moles CO2

For 1 mol C4H8 we need 6 moles O2 to produce 4 moles CO2 and 4 moles H2O

For 0.0146 moles we'll have 4*0.0146 = 0.0584 moles CO2

Step 6: Calculate Volume CO2

p*V = n*R*T

V = (n*R*T) /p

⇒ with V = the volume of CO2 = TO BE DETERMINED

⇒ with n = the moles of CO2 = 0.0584 moles

⇒ with R = the gas constant = 0.08206 L*atm / mol*K

⇒ with T = The temperature = 311.65 K

⇒ with p = the pressure = 0.355263 atm

V = (0.0584 * 0.08206 * 311.65) / 0.355263

V = 4.20 L

The volume of CO2 is 4.20 L

8 0
3 years ago
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