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maks197457 [2]
2 years ago
13

How many total atoms are in 0.450 grams of P2O5

Chemistry
1 answer:
Nady [450]2 years ago
8 0
First, we need to figure out the molar mass of P2O5. 

P x 2: 30.97g x 2 = 61.94g
O x 5: 16.00g x 5 = 80.00g
                           + 141.94g

0.450g x 1 mole/141.94g = 0.00317 moles = 3.17 x 10^3 moles

Now we are going to use Avogadro's number (=6.02 x 10^23)

(3.17 x 10^3 moles) x (6.02 x 10^23 atoms) / (1 mole) = 1.91 x 10^27 atoms


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Sergio039 [100]

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better check book pages for this kinda answer.

8 0
2 years ago
Choose the TRUE statement.
dsp73

Mass is calculated by using an objects inertia. Since inertia is a quality of matter that resists motion, we can apply an increasing force to an object until it accelerates.

Then, by measuring its acceleration we can now determine its mass using the simple equation F=m×a, except rewritten as m=Fa.

So we divide the force that we applied by the acceleration rate and we get the objects mass.

Without inertia this cannot be done.


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3 0
3 years ago
PLEASE EXPLAIN I KNOW THE ANSWER I NEED AN EXPLAINATION
BaLLatris [955]

From the graph shown, Y2 = N2, X2 = O2, Z2 = H2.

When atoms of elements are at a large distance from each other, the potential energy of the system is high. However, as the atoms approach each other, the potential energy of the system decreases steadily. The closer the atoms come to each other, the lower the potential energy. This implies that potential energy is proportional to bond length.

Since N2 has a shorter bond length and higher energy, Y2 must be N2. The bond energy of hydrogen is small hence H2 must be X2. The bond energy of a double bond is intermediate between that of a single and triple bond hence Z2 must be O2.

Learn more: brainly.com/question/24857760

6 0
2 years ago
Calculate the value of 0.1394÷0.004 showing all workings​
Lesechka [4]

Answer:

34.85

Explanation:

3 0
3 years ago
When [H+] = 4.0 × 10–9 M in water at 25°C, then
Salsk061 [2.6K]

Answer:

a. Kw = 1.0 × 10⁻¹⁴

Explanation:

a. Let's consider the self-ionization of water.

2 H₂O(l) ⇄ H₃O⁺(aq) + OH⁻

The ion-product of water (Kw) at 25 °C is:

Kw = [H₃O⁺][OH⁻] = 1.0 × 10⁻¹⁴

c. Considering [H⁺] = [H₃O⁺] = 4.0 × 10⁻⁹ M, the concentration of OH⁻ is:

[OH⁻] = 1.0 × 10⁻¹⁴/[H₃O⁺] = 2.5 × 10⁻⁶ M

b. We can calculate the pOH using the following expression.

pOH = -log [OH⁻] = -log 2.5 × 10⁻⁶ = 5.6

d. We can calculate the pH using the following expression.

pH = -log [H⁺] = -log 4.0 × 10⁻⁹ = 8.4

5 0
2 years ago
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