C - (x-3)^2=36
If we expand (x-3)^2=36:
(x-3)(x-3)=36
x^2-3x-3x+9=36
x^2-6x+9=36
Then subtract 36
x^2-6x-27=0
10 + 4*3 + 4*2 + 5 + 2 =
<span>10 + 12 + 8 +7 = </span>
<span>22 + 8 +7 = </span>
<span>30 + 7 =37</span>
Answer: (‑(15*x))+39
Step-by-step explanation:
