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3 years ago

I am so confused please

Mathematics

2 answers:

sashaice [31]3 years ago

6 0

1) 8a
2) 2x
3) 8k
4) 19.25c
5) 11y-5
6) .25x+2
7) 7t+14
8) 3.2k+5
9) z+6x
10) 3n+4p
11) 2y+2x
12) 27g-3s
13) 11m+100
14) 2w+12
15) 3b+10
16) 7a+6
17) 16n+10
18) 3y+6x
19) 15p/2
20) 3s-2t

Len [333]3 years ago

4 0

What the other guy said is correct :)

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The length of the line segment BC is 31.2 units.

<h2>Given that</h2>

Triangle ABC is shown.

Angle ABC is a right angle.

An altitude is drawn from point B to point D on side AC to form a right angle.

The length of AD is 5 and the length of BD is 12.

<h3>We have to determine</h3>

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<h3>According to the question</h3>

The altitude of the triangle is given by;

$\rm Altitude = \sqrt{xy}$

Where x is DC and y is 5 units.

Then,

The length DC is.

$\rm Altitude = \sqrt{xy}\\
\\
12 = \sqrt{(DC) \times 5}\\
\\
\sqrt{DC } = \dfrac{12}{\sqrt{5}}\\
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Squaring on both sides

$\rm DC = \dfrac{144}{5}\\
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Considering right triangle BDC, use the Pythagorean theorem to find BC:

$\rm BC^2 = DC^2+BD^2\\\\ BC^2 = (28.8)^2+(12)^2\\

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BC = \sqrt{829.44+144}\\
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BC = \sqrt{973.44}\\
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\rm BC = 31.2 \ units$

Hence, the length of the line segment BC is 31.2 units.

To know more about Pythagoras Theorem click the link given below.

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Step-by-step explanation:

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