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2 years ago

8. What is the slope of the graph below

Mathematics

2 answers:

NeTakaya2 years ago

5 0

Answer:

The answer is (0.5,10) mate

Roman55 [17]2 years ago

3 0

Answer:

Step-by-step explanation:

We need two points to use the slope formula

(0,0) and ( 4,80)

The slope is given by

m = ( y2-y1)/(x2-x1)

= ( 80-0)/(4-0)

= 80/4

= 20

The slope is 20

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(20 points and brainlest to whoever answers correctly!!!)

Stells [14]

Answer:

y = -2/3x - 11

Step-by-step explanation:

Steps to find the perpendicular bisector:

1) Find the midpoint of line PQ

Midpoint formula: ( $\frac{x_{1} + x_{2} }{2} \\$ , $\frac{y_{1} + y_{2}}{2}$ )

Midpoint of line PQ = (6, -2)

2) Find the slope of line PQ

Slope formula: $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Slope of line PQ = 3/2

3) Find the negative reciprocal of the slope of PQ

To find the negative reciprocal just swap the numerator and denominator and add a negative sign. If it is already negative it will become positive.

In this case it will be -2/3

4) Write the equation of line PQ in slop-intercept form.

Slope-intercept form: y = mx + b

This is what it will look like for line PQ: y = $\frac{3}{2}$ x + b

5) Plug the points of the midpoint into the line and solve for the intercept (b)

This is what it will look like: -2 = $\frac{3}{2}$ (6) + b

-2 = 18/2 + b

-2 = 9 + b

-11 = b

6) Write the equation of the perpendicular bisector

m = the negative reciprocal of the slope of PQ = -2/3

This is what the equation will look like: y = -2/3x - 11

Hope this helped! Please give Brainliest!

5 0

2 years ago

(1 point) If p(x) and (x) are arbitrary polynomials of degree at most 2, then the mapping =p(-1)q(-1) + p(070) +p(3)q(3) defines

Ainat [17]

If p(x) and q(x) are arbitrary polynomials of degree at most 2 then

||p||||q|| = 26( $\sqrt{640}$ ) and angle between p(x) and q(x) is 0.233.

Given that

<p,q> = p(-1)q(-1) + p(0) q(0) + p(3)q(3)

and p(x) = 2x²+ 6 , q(x)= 4x²-4x

then the values of p and q at x = -1,0,3 are given as;

x = -1,

p(-1) = 2(-1)² + 6 = 8 , q(-1) = 4(-1)² - 4(-1) = 8

x = 0,

p(0) = 2(0)² + 6 = 6 , q(0) = 4(0)² - 4(0) = 0

x = 3,

p(3) = 2(3)² + 6 = 24 , q(3) = 4(3)²- 4(3) = 24.

<p,q> = p(-1)q(-1) + p(0)q(0) + p(3)q(3)

= (8)(8) + (6)(0) + 24(24)

= 64 + 0 + 576

<p,q> = 640

Now we have to find ||p|| ||q||, for this we'll find ||p|| and ||q||

||p|| = $\sqrt{ < p,p > }$

= $\sqrt{8(8) + 6(6) + 24(24)}$

= $\sqrt{676}$

||p|| = 26

and

||q|| = $\sqrt{ < q,q > }$

= $\sqrt{8(8) + 0(0) + 24(24)}$

||q|| = $\sqrt{640}$

∴||p||||q|| = 26( $\sqrt{640\\$ )

Now we have to find angle between p(x) and q(x),

∴ α = cos⁻¹ $\frac{ < p,q > }{||p||||q||}$

= cos ⁻¹ $\frac{640}{26(\sqrt{640}) }$

= cos ⁻¹ $\frac{4\sqrt{10} }{13}$

α = 13.34°

In radian

α = 0.233.

To know more about Inner product here

brainly.com/question/14185022

#SPJ4

5 0

9 months ago

15q – 4r = 62<br> 5q + 8r = 86

KIM [24]

Answer:

q = 6; r = 7

Step-by-step explanation:

3 0

2 years ago

The Russian ice breaker yamal can move forward through 2.3-meter-thick ice at a speed of 5.5 kilometers per hour. Write and solv

aleksandrvk [35]

82.5 / 5.5 = 15

15 hrs.

i think that should be the answer but i didn't use the 2.3 -meter-thick clue...

8 0

3 years ago

The area of the shaded region of the figure is _____ mm ²

solniwko [45]

Answer:

400mm^2

Step-by-step explanation:

8 0

2 years ago