3 years ago

(a+5)4 binomial theorem

Mathematics

1 answer:

Ann [662]3 years ago

5 0

Answer:

a⁴ + 20a³ + 150a² + 500a + 625

Step-by-step explanation:

(a + 5)⁴

₄C₀ a⁴ 5⁰ + ₄C₁ a³ 5¹ + ₄C₂ a² 5² + ₄C₃ a¹ 5³ + ₄C₄ a⁰ 5⁴

a⁴ + 4 a³ 5 + 6 a² 25 + 4 a 125 + 625

a⁴ + 20a³ + 150a² + 500a + 625

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Graph 2x-5=2x+8 please

lapo4ka [179]

2x-5=2x+8
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y=2x-5
y=2x+8

4 0

4 years ago

How to evaluate the limit

anzhelika [568]

$\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}$

Both the numerator and denominator are continuous at $x=2$ , which means the quotient rule for limits applies:

$\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2$

Perhaps you meant to write that $x\to-2$ instead? In that case, you would have

$\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5$