Answer:
I'm gonna use the distance formula:
Distance = sqrt((x2-x1)^2 + (y2-y1)^2)
Distance = sqrt((6-3)^2 + (13-9)^2)
Distance = sqrt(3^2 + 4^2)
Distance = sqrt(9 + 16)
Distance = sqrt(25)
Distance = 5
The problem says every unit = 1 mile so 5 units = 5 miles.
Answer = 5 miles
Step-by-step explanation:
9514 1404 393
Answer:
5/9 m/min
Step-by-step explanation:
The depth of the water is 2/5 of the depth of the trough, so the width of the surface will be 2/5 of the width of the trough:
2/5 × 2 m = 4/5 m
Then the surface area of the water is ...
A = LW = (18 m)(4/5 m) = 14.4 m²
The rate of change of height multiplied by the area gives the rate of change of volume:
8 m³/min = (14.4 m²)(h')
h' = (8 m³/min)/(14.4 m²) = 5/9 m/min
Answer: This is how I would do it 8x67=402
Step-by-step explanation:
A/b *100
For example,
30/600.
30/600=0.05
0.05*100=5%
