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iren [92.7K]
3 years ago
15

800 is 10 times as much as ---------

Mathematics
2 answers:
amm18123 years ago
3 0
The answer to your question is 80 because 10 times 80 equals 800
oksian1 [2.3K]3 years ago
3 0
80 because 80x 10= 800

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A rectangular fence is 27.8 meters by 34.2 meters.what is its the perimeter answer
storchak [24]

The perimeter of a rectangle is calculated as

Perimeter= 2(length + breadth )

So, Perimeter = 2*length + 2*breadth

Now we are given the length as 34.2 meters and breadth as 27.8 meters

So the perimeter will be

2(34.2+27.8) meters

(2*34.2) + (2*27.8)

which equals 2(62) meters

Hence Perimeter = 124 meters

5 0
3 years ago
Find the midpoint of (0,4) and (-4,-12)
ankoles [38]
The answer is (-2,-4) to solve this you need to add the X’s and divide by 2 and that will be your X for the midpoint, you do the same with the Y’s to find the y for your midpoint
5 0
3 years ago
Select the equation in slope-intercept form that is equivalent to: 4x + 3y = 12
sattari [20]

Answer:

y = -4/3x +4

Step-by-step explanation:

y= mx+b

solve for y.

4x+3y=12

Step 1: Add -4x to both sides.

4x+3y+−4x=12+−4x

3y=−4x+12

Step 2: Divide both sides by 3.

Let's solve for y.

4x+3y=12

Step 1: Add -4x to both sides.

4x+3y+−4x=12+−4x

3y=−4x+12

Step 2: Divide both sides by 3.

3y / 3 =-4x +12 /3

y = -4/3x +4

hopes this helps you out

5 0
3 years ago
What’s the correct answer for this question?
Brut [27]

Answer:

C.

Step-by-step explanation:

First finding height using Pythagoras theorem

(H)²=(B)²+(P)²

8.2²=5.4²+P²

P² = 67.24 - 29.16

P² = 38.08

P = 6.2

Now

Volume of cone = (1/3)πr²h

= (1/3)(3.14)(5.4)²(6.2)

= (1/3)(567.9)

= 189.2 cm³

6 0
3 years ago
A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Four hu
castortr0y [4]

<em>Answer: h = 120 ft;    w = 80 ft </em>

<em></em>

<em>A = 9600 ft^2</em>

<em />

<em>Step-by-step explanation: Let h and w be the dimensions of the playground. The area is given by:</em>

<em></em>

<em>A = h*w   (eq1)</em>

<em></em>

<em>The total amount of fence used is:</em>

<em></em>

<em>L = 2*h + 2*w + w    (eq2)    (an extra distance w beacuse of the division)</em>

<em></em>

<em>Solving for w:</em>

<em></em>

<em>w = L - 2/3*h = 480 - 2/3*h   (eq3)  Replacing this into the area eq:</em>

<em></em>

<em></em>

<em></em>

<em>We derive this and equal zero to find its maximum:</em>

<em></em>

<em>   Solving for h:</em>

<em></em>

<em>h = 120 ft.  Replacing this into eq3:</em>

<em></em>

<em>w = 80ft</em>

<em></em>

<em>Therefore the maximum area is:</em>

<em></em>

<em>A = 9600 ft^2</em>

<em />

5 0
3 years ago
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