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goldfiish [28.3K]
3 years ago
11

when a linear function is graphed it passes through the points (-1,1), (1,5), and (3,9) what is the rate of change for the funct

ion?
Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0
Use the linear slope formula to solve for m: 

m=(y2-y1)/(x2-x1)

using the points (-1,1) and (1,5) you can find the slope for the first interval:
 
m=(5-1)/(1-(-1))
m=4/2
m=2

you can double check by using the same formula on the second interval, which is (1,5) to (3,9).

m=(9-5)/(3-1)
m=4/2
m=2 

therefore, the rate of change is 2. 
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Use repeated addition to find the solution to each multiplication problem. Change any improper fractions to mixed numbers. 4x1/3
Nata [24]

Answer:

1\frac{1}{3}

Step-by-step explanation:

Given the following question:

4\times\frac{1}{3}

To find the answer simply multiply the numerators and the denominators by each other.

4\times\frac{1}{3}
4=\frac{4}{1}
\frac{4}{1} \times\frac{1}{3}
4\times1=4
1\times3=3
=\frac{4}{3}
\frac{4}{3} =4\div3=1\frac{1}{3}
1\frac{1}{3}

Hope this helps.

7 0
2 years ago
Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

3 0
2 years ago
Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t
Gnom [1K]

Answer:

Second class have higher marks and greater spread.

Step-by-step explanation:

First box plot  represents class first. From the first box plot, we get

\text{Minimum value }= 53,Q_1=62,Median=80,Q_3=86,\text{Maximum value }= 89

Range=Maximum-Minimum=89-53=36

IQR=Q_3-Q-1=86-62=24

Second box plot  represents class second. From the second box plot, we get

\text{Minimum value }= 56,Q_1=62,Median=74,Q_3=89,\text{Maximum value }= 96

Range=Maximum-Minimum=96-56=40

IQR=Q_3-Q-1=89-62=27

First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.

Second class has greater range and greater inter quartile range. It means data of second class has greater spread.

Therefore, second class have higher marks and greater spread.

3 0
3 years ago
Everyday 3 days Marco fills up his car with gas. Every 8 days he washes his car . On what day will Marco fill his car up with ga
GaryK [48]
3, 6, 9, 12,15, 18, 21, 24
8, 16, 24

Marco will fill up his car with gas and wash it on the 24th day.
7 0
3 years ago
Read 2 more answers
The geometry of the hybrid orbitals about a central atom with sp3d hybridization is:________
Lyrx [107]

For sp3d hybridized central atoms, the only possible molecular geometry is trigonal bipyramidal.

Hybridisation (or hybridization) is a process of mathematically combining two or more atomic orbitals from the same atom to form an entirely new orbital different from its components and hence being called as a hybrid orbital.

In this case, if all the bonds are in place, the shape is also trigonal bipyramidal.

In chemistry, a trigonal bipyramid formation is a molecular geometry with one atom at the center and 5 more atoms at the corners of a triangular bipyramid.

Bond angle(s): 90°, 120°

Coordination number: 5

Point group: D3h

For more information about orbitals, visit

brainly.com/question/25886221

#SPJ4

8 0
1 year ago
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