The correct answer is C. A linear equation is written in y=mx+b, which this equation can be. y=3-4x is the same as y=-4x+3, which is a linear function.
Hello!
<u>Number 22
</u>
: We'd plot the first point at 0 since there is no stated y-intercept. Next, we'd use our slope to determine where to plot the next point, and that would create our line. According to the problem, our slope is

, which automatically tells us that the slope would be going downwards because it's negative.
To plot our point, use the slope while going down and across from our y-intercept, which is 0. Go down 1, and over 2.
Your points should be at (0, 0) and (-1, 2)
<u /><u>Number 23:</u> This one will be a bit trickier since the equation is not in slope-intercept form. First, let's convert it to slope-intercept form.

Flip some of those numbers around to get our equation in slope-intercept form:

Now to graph this, we do the same as we did for the last problem. Plot our first point at (0, 2), since 2 is our y-intercept. Afterwards, go up 2 and over 3, then plot the other point.
Your points should be at (0, 2) and (4, 3)
Distance formula: √((y2-y1)^2+(x2-x1)^2)
Plug in the values √((4-2)^2+(6-3)^2)
√((2)^2+(3)^2) = √(4+9) = √13 = 3.6
3.6 is your answer.
Answer:
ax²+ bx + c = 0
Step-by-step explanation
Multiplying (x+4) and (x−1) together (called Expanding) gets x2 + 3x − 4 :
expand vs factor quadratic
So (x+4) and (x−1) are factors of x2 + 3x − 4
Just to be sure, let us check:
(x+4)(x−1) = x(x−1) + 4(x−1)
= x2 − x + 4x − 4
= x2 + 3x − 4 yes
Yes, (x+4) and (x−1) are definitely factors of x2 + 3x − 4