This equation is written in slope intercept form
Remember that the slope intercept formula is:
y = mx + b
m is the slope
b is the y-intercept
In this case:
slope (m) is 2
y-intercept (b) is (0, - 1)
To plot this on a coordinate plane plot the y-intercept (0, -1).
To graph the rest of the line you can use what you know about the slope. Rise up two units and over to the right one unit from the y-intercept. You should arrive at the point (1, 1)
Then, again from the y-intercept, go down two units and to the left one unit. You should arrive at the point (-1, -3)
Now draw a straight line through the y-intercept and the other two points you just found
The image of the graph is shown below
Hope this helped!
~Just a girl in love with Shawn Mendes
In economics, the downward sloping demand curve is used to illustrate the law of diminishing marginal utility. This means that if more of the product is consumed, the marginal benefit to the consumer falls. This is also the instance in which the consumers are willing to pay less than the original amount for the same product.
Answer:
y = 5x-11
Step-by-step explanation:
The slope intercept form of a line is y =mx+b where m is the slope
y = -1/5 x-3
The slope is -1/5
Lines that are perpendicular have negative reciprocal slopes
-1 /(-1/5)
-1 * -5/1
5
The slope of the line that is perpendicular is 5
y=5x+b
Using the point (4,9)
9 = 5(4)+b
9 = 20+b
9-20 =b
-11
y = 5x-11
Answer:
We accept H₀ with the information we have, we can say level of ozone is under the major limit
Step-by-step explanation:
Normal Distribution
population mean = μ₀ = 7.5 ppm
Sample size n = 16 df = n - 1 df = 15
Sample mean = μ = 7.8 ppm
Sample standard deviation = s = 0.8
We want to find out if ozono level, is above normal level that is bigger than 7.5
1.- Hypothesis Test
null hypothesis H₀ μ₀ = 7.5
alternative hypothesis Hₐ μ₀ > 7.5
2.-Significance level α = 0.01 we will develop one tail-test (right)
then for df = 15 and α = 0,01 from t -student table we get
t(c) = 2.624
3.-Compute t(s)
t(s) = ( μ - μ₀ ) / s /√n ⇒ t(s) = ( 7.8 - 7.5 )*4/0.8
t(s) = 0.3*4/0.8
t(s) = 1.5
4.-Compare t(s) and t(c)
t(s) < t(c) 1.5 < 2.64
Then t(s) is inside the acceptance region. We accept H₀
