Answer: You find midpoint by adding the two x values together and dividing by 2, then adding the two y values together and dividing by two.
Answer:
9.85
Step-by-step explanation:
I hate these, LOL
We're going to draw a triangle on the graph paper to solve this. (in theory)
The top point is at 2 on the x axis, and the bottom is at 6. That's a difference of 4. Draw a line from the top dot over 4 spaces, so a line dropped from there could go straight to the bottom dot. We'll call this line/side of the triangle a, and a = 4.
Then we drop the line from there (6, 4) down to the second dot at (6, -5). That line is 9 places long. We'll call this line/side of the triangle b, and b = 9.
(This is so much easier to draw than type, I'll attach a picture).
Then we connect the two dots diagonally to form line/side c of our triangle. This is the length we don't know.
The pythagorean theorem says a^2 + b^2 = c^2
So a = 4, b = 9, c is unknown for our triangle
(4)(4) + (9)(9) = c^2
16 + 81 = 97
The square root of 97 = 9.8488, so if they have you round, I would say 9.85
Sorry if this just confused you more.
Answer: D. 7
Step-by-step explanation:
The problem tells you that x = 0 so replace everything that is x in the equation with 0 so the problem becomes
7 + (-3(0)^2)
Now we just solve the problem normally.
solve the problem in the parenthesis first, we must multiply -3 times 0^2 is 0
so now our problem is 7 + 0 which is 7
Step-by-step explanation:
With each draw, the probability of selecting a green marble is 2/3 and the probability of selecting a yellow marble is 1/3.
To pick two of the the same color, they can either pick green twice or yellow twice.
P = (2/3)(2/3) + (1/3)(1/3)
P = 5/9
To pick two different colors, they can either pick green first then yellow, or yellow first then green.
P = (2/3)(1/3) + (1/3)(2/3)
P = 4/9
Expected value for Derek is:
D = (5/9)(-1) + (4/9)(1)
D = -1/9
The expected value for Mia is:
M = (5/9)(1) + (4/9)(-1)
M = 1/9
Answer: If you mean the math definiton then a quantity or parameter that does not change its value whatever the value of the variables, under a given set of conditions.