Please help me with this math question!
1 answer:
The bases are both 2, so we would subtract the exponents. This is because the rule is
(a^b)/(a^c) = a^(b-c)
In this case,
a = 2
b = 3/4
c = 1/2
So this means
b - c = (3/4) - (1/2) = (3/4) - (2/4) = 1/4
After subtracting the exponents, the final exponent is 1/4
So the expression simplifies to 2^(1/4) which is the same as![\sqrt[4]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D)
(fourth root of 2)
(a^b)/(a^c) = a^(b-c)
In this case,
a = 2
b = 3/4
c = 1/2
So this means
b - c = (3/4) - (1/2) = (3/4) - (2/4) = 1/4
After subtracting the exponents, the final exponent is 1/4
So the expression simplifies to 2^(1/4) which is the same as
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Step-by-step explanation:
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Answer:
(h,k) = (32,-4)
r = 32
Step-by-step explanation:
The general equation for a circle is given by:
(1)
where (h,k) is the center of the circle and r is the radius.
You have the following equation:
(2)
You first need to complete squares in order to obtain an equation of the form (1). Thus, you have that the second term must be in a perfect square trinomial:
2b = 64
b = 32
Then, you have to sum 32^2 and also subtract the same number in the expression (2):
you compare the last result with expression (1) and obtain that the raiuds of the circle is r = 32
Furthermore, the center of the circle is (h,k) = (32,-4)