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nekit [7.7K]
3 years ago
14

Through point (0, 10) and PERPENDICULAR to the line through (-2, -9) and (-4, -17)?

Mathematics
1 answer:
inn [45]3 years ago
3 0

Compute the slope of the line through (-2, -9) and (-4, -17):

\dfrac{-9-(-17)}{-2-(-4)}=\dfrac82=4

Any line perpendicular to this line will have slope -1/4. The one that passes through (0, 10) satisifes

y-10=-\dfrac14(x-0)\implies\boxed{y=10-\dfrac x4}

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4 0
3 years ago
Please help!!!!! pls pls pls asap
kow [346]

Answer: 78

Step-by-step explanation:

First, we want to find the area of the outer triangles. Remember that the equation to finding the area of a triangle is (l x h) x 1/2. So, let’s substitute the values into the equation. It’ll be (6 x 7) x 1/2. Let’s solve! 6 x 7 = 42. Then, 42 x 1/2 = 21. But let’s not forget that we only found the area of one triangle. We still need to find the area of the other outer triangles. So, to do this, we take 21 and multiply by 3 since the other outer triangles have the same dimensions. We would get 63 as our total area for the outer triangles.

Next, we need to find the area for the inner triangle. We will use the same equation: (l x h) x 1/2. Let’s substitute! (6 x 5) x 1/2 will be our final equation. Now, let’s solve. 6 x 5 = 30. 30 x 1/2 = 15. So, as a process of elimination, our area for the inner triangle is 15.

Finally, we need to add the total areas we found together. Our total areas were 63 and 15. Let’s put this into an equation: 63 + 15 = ?. So, 63 + 15 = 78. So, after a long process, 15 is our answer!

Hope this helped!

6 0
3 years ago
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Ymorist [56]

Answer:

open circle on -7 going right to 12

idk the first part tho, sorry

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