M < 2 and m < 3 are supplementary angles which add up to 180 degrees.
< 2 + < 3 = 180
3x + 17 + 5x - 21 = 180
8x - 4 = 180
8x = 180 + 4
8x = 184
x = 184/8
x = 23
m < 2 = 3x + 17 = 3(23) + 17 = 69 + 17 = 86 degrees
m < 3 = 5x - 21 = 5(23) - 21 = 115 - 21 = 94 degrees
m < 1 and m < 2 are corresponding angles....they are equal.
so m < 1 = 86 degrees <===
The angle of elevation is = 70° and the distance the airplane travelled in the air is = 17,557ft
<h3>Calculation of the distance travelled</h3>
- To calculate the angle of elevation of the airplane
tan x° = opposite/adjacent
where opposite = 16,500 feet
adjacent = 6,000 ft
tan x° = 16,500 / 6,000
tan x° = 2.75
X = arctan ( 2.75)
X = 70°
- To calculate the distance the airplane travelled in the air Pythagorean Theorem is used.
C² = a² + b²
C² = 16,500² + 6,000²
C² = 272250000 + 36000000
C² = 308250000
C= √308250000
C= 17,557ft
Learn more about Pythagorean Theorem here:
brainly.com/question/343682
#SPJ1
Answer:
289 cm²
Step-by-step explanation:
Length (L) = 17 cm
Area of a square
= L²
= (17cm)²
= 289 cm²
Answer: a. 0.6759 b. 0.3752 c. 0.1480
Step-by-step explanation:
Given : The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes
i.e.
minutes
minutes
Let x be the long-distance call length.
a. The probability that a call lasts between 5 and 10 minutes will be :-

b. The probability that a call lasts more than 7 minutes. :
![P(X>7)=P(\dfrac{X-\mu}{\sigma}>\dfrac{7-6.3}{2.2})\\\\=P(Z>0.318)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E7%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B7-6.3%7D%7B2.2%7D%29%5C%5C%5C%5C%3DP%28Z%3E0.318%29%5C%20%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C0.318%29%5C%5C%5C%5C%3D1-0.6248%5C%20%5C%20%5C%20%5C%20%5B%5Ctext%7Bby%20z-table%7D%5D%5C%5C%5C%5C%3D0.3752)
c. The probability that a call lasts more than 4 minutes. :

It is £15 for the words, but I don’t understand the second part