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stiks02 [169]
3 years ago
13

katie collets stamp she has stamps from canada, United Staes,ands Rest of the world in a ratio of 1:1.2:1.5 she has 135 stamps f

rom rest of the world
Mathematics
1 answer:
lyudmila [28]3 years ago
8 0

Answer:

90 stamps from Canada, 108 stamps from the United States, and 135 stamps from the Rest of the World

Step-by-step explanation:

Since this is a problem of proportion we can use the Rule of three to solve this. We do this by multiplying the diagonal available values and dividing by the third value in order to get the missing variable, which in this case would be the number of stamps in the other country. Like so...

1.5  <=====>  135 stamps

1.2  <=====>  x  stamps (United States)

(1.2 * 135) / 1.5 = 108 stamps (United States)

1.5  <=====>  135 stamps

1  <=====>  x  stamps (Canada)

(1 * 135) / 1.5 = 90 stamps (Canada)

Finally, we can see that Katie had 90 stamps from Canada, 108 stamps from the United States, and 135 stamps from the Rest of the World. All creating a ratio or 1:1.2:1.5

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Answer:

280 mangoes

Step-by-step explanation:

sum the parts of the ratio, 7 + 11 = 18 parts

Divide the total by 18 to find the value of one part of the ratio.

720 ÷ 18 = 40 ← value of 1 part of the ratio , then

7 × 40 = 280 ← number of mangoes

8 0
2 years ago
Read 2 more answers
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Hoochie [10]
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3 years ago
2.
laiz [17]

Answer:

B) 0.02

Step-by-step explanation:

<u>Use the Binomial Theorem</u>

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We have the probability of success, p=0.30, and the probability of failure, q=1-0.30=0.70. The binomial coefficient, \binom{n}{k}, represents the amount of possible combinations that k items can be chosen out of n items, with its respective formula \frac{n!}{k!(n-k)!}.

Hence, the best choice for the probability that 4 students chosen at random from the class of 30 that want the next test to be on Monday will be option B, 0.02

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2 years ago
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3 years ago
1. What is the probability of getting a number greater than 2 on two rolls of a six-sided die both times?
prisoha [69]

Answer:

For this question, the options are written the wrong way. In each of the answers below, the correct form of the question will be added.  

The answers are:

1. e) 4/9

2. a) 1/16

3. 980 girls

4. c) 2/3

5. d) 1/13

6. a) 42 boys

7. d) 1/21

8. b) 1/6

Step-by-step explanation:

1. What is the probability of getting a number greater than 2 on two rolls of a six-sided die both times?

a) 4/3

b) 2/6

c) 4/6

d) 3/6

e) 4/9

The correct answer is e) 4/9 because the probability of getting a number greater than 2 in two rolls is 4/6 * 4/6 =16/36 = 4/9

2. A fair coin is tossed four times. What is the probability that it will be heads every time?

a) 1/16

b) 4/2

c) 2

d) 4/16

e) 1

The correct answer is a) 1/16 because the probability of each time that the coin is tossed is 1/2, and for 4 tosses is 1/2*1/2*1/2*1/2 = 1/16

3. The ratio of the number of girls to the number of boys was 2 to 5. If 2,450 students were present, how many were girls and how many were boys?

The correct answer is 980 girls, because 2450*2/5 = 980

4. A die is rolled twice. What is the probability of rolling a 5 or getting an even number?

a) 3/1

b) 1/12

c) 2/3

d) 1/3

If the die is rolled twice there are 12 possible outcomes and 8 of those outcomes can be 5 or an even number. The probability is 8/12 = 2/3

5. If one card is drawn from a standard deck, what is the probability of getting a jack?

a) 4/13

b) 1/52

c) 52

d) 1/13

e) 4

In a standard deck, there are 13 jack cards, the probability of getting a jack the first time is 1/13

6. There are 210 boys trying out for football. If 20% made the team, how many were chosen?

a) 42

b) 10

c) 4200

d) 105

e) 20

The number of boys that will be picked for the team is 210*20% = 42

7. From 42 boys who made the team, one will be chosen as kicker and one will be chosen as quarterback. What is the probability of being chosen as the kicker or the quarterback?

a) 2/21

b) 1/42

c) 2

d) 1/21

e) 42

The probability of getting picked for one of the 2 positions is 2/42 = 1/21

8. Two dice are rolled. There are 36 possible outcomes of rolling two dice. What is the probability of getting a total of seven on one roll?

a) 7

b) 1/6

c) 0

d) 7/36

e) 1/36

There are 6 ways of getting a sum of 7 tossing 2 dice, 1+6, 6+1, 2+5, 5+2, 3+4, 4+3. The probability is 6/36 = 1/6

3 0
3 years ago
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