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4 years ago

12

9x^2+6x+5=0, solve using the quadratic formula

1 answer:

AleksAgata [21]4 years ago

8 0

Step by step explanation:

9 $x^{2}$ +6x+5=0

Uses the "a", "b", and "c" from "a $x^{2}$ + bx + c", where "a", "b", and "c" are numbers

So in this case:

a would be 9

b would be 6

c would be 5

Then plug in from there..

Another way you can do it is using the square method.

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Solve the absolute value equation algebraically, -8|-x-6|+10=2

enot [183]

-8|-x-6|+10=2
-8|-x-6|+10-10=2-10
-8|-x-6|=-8
(-8|-x-6|=-8)/-8
|-x-6|=1
then -x-6=-1 or -x-6=1
first one equals x=-5 (-x-6=-1)
second one equals x=-7 (-x-6=1)

hope this helps..

4 0

3 years ago

Round off 452 to the nearest 100

belka [17]

Answer:

500

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If 12 cows produce 70 gallons of milk, how many gallons of milk would 42 cows produce?

I am Lyosha [343]

This is a proportions question
12 42
------ = -------
70 ?

Cross multiply

70x42=2940
12x?=2940
294/12=245

42 cows can produce 245 gallons of milk.
So the answer is B.

Hope I helped!

4 0

3 years ago

Read 2 more answers

The length of a rectangle is 5 inches more than its vedth. The area of the rectangle is equal to

jarptica [38.1K]

Answer:

The width = x = 14

The length = x+5 = 14+5 = 19

Step-by-step explanation:

Let l = length, w = width, A = area = l×w , and P = perimeter = 2(l+w)

Let 'x' be the width

As the length 'l' of a rectangle is 5 inches more than its width.

so the length will be = x+5

As the Area of the rectangle is equal to 2 inches more than 4 times the perimeter.

A = 4P + 2

so the equation becomes

l × w = 4×2(l+w)+2

substituting w=x, l = x+5,

(x+5)x = 8(x+5+x)+2

x²+5x = 8(5+2x)+2

x²+5x = 40+16x+2

x²+5x = 16x+42

x²+5x-16x-42 =0

x²-11x-42=0

$x^2-11x=42$

$\mathrm{Add\:}a^2=\left(-\frac{11}{2}\right)^2\mathrm{\:to\:both\:sides}$

$x^2-11x+\left(-\frac{11}{2}\right)^2=42+\left(-\frac{11}{2}\right)^2$

$x^2-11x+\left(-\frac{11}{2}\right)^2=\frac{289}{4}$

$\left(x-\frac{11}{2}\right)^2=\frac{289}{4}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{11}{2}=\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{\sqrt{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{2}$

$x-\frac{11}{2}=\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=\frac{17}{2}+\frac{11}{2}$

$x=14$

similarly solving

$x-\frac{11}{2}=-\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=-\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=-\frac{17}{2}+\frac{11}{2}$

$x=-3$

so

x = 14, or x = -3

As the width 'x' can not be negative.

so x = 14

Thus,

The width = x = 14

The length = x+5 = 14+5 = 19

6 0

3 years ago

Qual o resultado da subtração dos dois polinômios abaixo? (2x2 + 4x) (–2x2 + x – 6)

Len [333]

Answer:

-4x^4-6x^3-8x^2-24x

Step-by-step explanation:

$\left(2x^2+4x\right)\left(-2x^2+x-6\right)\\$

distribuir parênteses

$=2x^2\left(-2x^2\right)+2x^2x+2x^2\left(-6\right)+4x\left(-2x^2\right)+4xx+4x\left(-6\right)$

Aplicar regras de menos mais ; $+\left(-a\right)=-a$

$=-2\times\:2x^2x^2+2x^2x-2\times\:6x^2-4\times\:2x^2x+4xx-4\times\:6x$

simplificar

$-2\times\:2x^2x^2+2x^2x-2\times\:6x^2-4\times\:2x^2x+4xx-4\times\:6x:\\\quad -4x^4-6x^3-8x^2-24x$

7 0

4 years ago