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Ann [662]
4 years ago
12

9x^2+6x+5=0, solve using the quadratic formula

Mathematics
1 answer:
AleksAgata [21]4 years ago
8 0

Step by step explanation:

9x^{2}+6x+5=0

Uses the "a", "b", and "c" from "ax^{2} + bx + c", where "a", "b", and "c" are numbers

So in this case:

a would be 9

b would be 6

c would be 5

Then plug in from there..

Another way you can do it is using the square method.

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Orginal price=$86 discounted price=$64.5 discount=?
Alenkinab [10]
The answer would be $21.5 less than the original.
4 0
3 years ago
Suppose that 20% of the adult women in the United States dye or highlight their hair. We would like to know the probability that
Rasek [7]

Answer:

71.08% probability that pˆ takes a value between 0.17 and 0.23.

Step-by-step explanation:

We use the binomial approxiation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.2, n = 200. So

\mu = E(X) = np = 200*0.2 = 40

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.2*0.8} = 5.66

In other words, find probability that pˆ takes a value between 0.17 and 0.23.

This probability is the pvalue of Z when X = 200*0.23 = 46 subtracted by the pvalue of Z when X = 200*0.17 = 34. So

X = 46

Z = \frac{X - \mu}{\sigma}

Z = \frac{46 - 40}{5.66}

Z = 1.06

Z = 1.06 has a pvalue of 0.8554

X = 34

Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 40}{5.66}

Z = -1.06

Z = -1.06 has a pvalue of 0.1446

0.8554 - 0.1446 = 0.7108

71.08% probability that pˆ takes a value between 0.17 and 0.23.

6 0
3 years ago
BRAINLIEST + 20 POINTS!!! plz help
Citrus2011 [14]

Answer:

d

Step-by-step explanation:

6 0
3 years ago
Which postulate or theorem proves that △ABC and △EDC are congruent?
Lelechka [254]

Answer:

SAS

Step-by-step explanation:

You are already given that two sides are congruent, thus making the "s" part. You can further say that two angles are congruent, due to the verticle angle theorem!

5 0
3 years ago
The some of the squares of two consecutive integers is 145. Find the integers.
garik1379 [7]
The 2 numbers are 8 and 9.
8^2=64
9^2=81
<span>81+64=145</span>
4 0
3 years ago
Read 2 more answers
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