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mart [117]
2 years ago
5

Urgent!

Mathematics
1 answer:
Novay_Z [31]2 years ago
3 0

Answer:

Segment BF = 15

Step-by-step explanation:

Segment DE is parallel to segment BC

Segment EF is parallel to segment AB.

Because segment EF is parallel to segment AB, triangles ADE and EFC are proportional. We must find the scale factor which these two triangles are proportional.

24 ÷ 20 = 1.2

Scale Factor = 1.2

18 ÷ 1.2 = 15

Segment EF is parallel to segment AB so segment EF is congruent to segment DB.

hope this helps! ps. im very sorry about the previous wrong question, but i hope this is right (,,>﹏<,,) xx

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15.6

Step-by-step explanation:

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What is the quotient of -3/8 and -1/3?<br><br> A. -1 1/8<br> B. -1/8<br> C. 1/8<br> D. 1 1/8
kobusy [5.1K]

Answer:

d. 1 1/8

Step-by-step explanation:

-3 -1

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5 0
3 years ago
What is the value of x?
Hitman42 [59]
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3 years ago
A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc
lisov135 [29]

Answer:

The answer is option (C), One cement bridge post weighs 9,135 pounds

Step-by-step explanation:

Step 1: Get the total volume of a cement bridge post

The cement bridge post is in the shape of a cuboid, therefor the volume of the cement bridge post can be expressed as;

Volume of cement bridge post=Base area×Length

where;

Base area=(24^2) inches square

1 foot=12 inches

Convert 24 inches to foot=24/12=2^2=4 feet²

Length=15 feet and 9 inches

1 foot=12 inches

Convert 9 inches to foot=9/12=0.75 feet

Total length=(15+0.75)=15.75 feet

replacing;

Volume of cement bridge post=(4×15.75)=63 cubic feet

Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

Total weight of the cement bridge post=Weight per cubic foot×total volume of the cement bridge post

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replacing;

Total weight of the cement bridge post=(145×63)=9,135 pounds

One cement bridge post weighs 9,135 pounds

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