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2 years ago

Urgent!

Mathematics

1 answer:

Novay_Z [31]2 years ago

3 0

Answer:

Segment BF = 15

Step-by-step explanation:

Segment DE is parallel to segment BC

Segment EF is parallel to segment AB.

Because segment EF is parallel to segment AB, triangles ADE and EFC are proportional. We must find the scale factor which these two triangles are proportional.

24 ÷ 20 = 1.2

Scale Factor = 1.2

18 ÷ 1.2 = 15

Segment EF is parallel to segment AB so segment EF is congruent to segment DB.

hope this helps! ps. im very sorry about the previous wrong question, but i hope this is right (,,>﹏<,,) xx

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Find x. Assume that segments that appear tangent are tangent.

kipiarov [429]

Assuming that CB is tangent, this is just a right triangle with a hypotenuse of 20 and a side of 12 so by the Pythagorean Theorem:

20^2=12^2+x^2

400=144+x^2

x^2=400-144

x^2=256

x=16

6 0

3 years ago

2. Check the boxes for the following sets that are closed under the given

son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Addition

c) AdditionSum

d) in this case we have two possibilities

* If we move to the right the addition

* If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

-3 -1 = -4

-4 -1 = -5

-7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) $0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}$ ...

In this case we can see more clearly the sequence when writing in this way

$0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}$

each term is found by adding 1 to the current term,

$\sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}$

Therefore the mathematical operation is the addition

c) $... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...$

The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

To move to the right add 1

- $\frac{-10}{2} + 1 = \frac{-10}{2} - \frac{2}{2} = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}$

To move left subtract 1

$\frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}$

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Sum

c) Sum

d) This case we have two possibilities

If we move to the right the sum

If we move to the left we subtract

Learn more here: brainly.com/question/4626313

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stira [4]

Answer:

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Step-by-step explanation:

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3 years ago

Which property should Remus use to solve the equation below? 7 q = 49 division property of equality addition property of equalit

AysviL [449]

The division property of equality should Remus used to solve the given equation and this can be determined by using the given data.

Given :

Equation is $7q = 49$ .