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irina [24]
3 years ago
6

Find two unit vectors in 2-space that make an angle of 45◦ with 4i+3j.

Mathematics
1 answer:
inn [45]3 years ago
4 0
First, lets transform the given vector into an unit vector (dividing by its module)


UnitVec = 4/5 i + 3/5 j

Then lets change this vector into a polar form

UnitVec = 1. with angle of 36.869 degrees taking as a reference the i vector

Then, the probem tells us that the vectors u and v make an angle of 45 degrees with UnitVec, so lets add+-45 to the vector in polar form

U = 1*[cos(
36.869 +45)i + sin(36.869 +45)j] = 0.1414 i + 0.9899 j


V = 1*[cos(
36.869 -45)i + sin(36.869 -45)j] = 0.9899 i - 0.1414 j




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andrey2020 [161]

Answer:

Look to the attached graph

Step-by-step explanation:

* Lets revise how to graph the quadratic function

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- Find the x-intercept

∵ f(x) = (x - 5)² + 1 ⇒ the completing square form

- The completing square form for any quadratic is

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* Lets compare the two forms

∵ (x - h)² + k = (x - 5)² + 1

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∴ The vertex of the parabola is (5 , 1)

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∵ (x - 5)² + 1 = 0 ⇒ subtract 1 from both sides

∴ (x - 5)² = -1 ⇒ the square can not give -ve number

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- To find the y-intercept put x = 0

∵ f(0) = (0 - 5)² + 1 = 25 + 1 = 26

∴ The parabola intersects the y-axis at point (0 , 26)

- The parabola is opened upward because the coefficient of x² is +ve

* Now lets graph it

- Look to the attached graph

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Answer:

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Step-by-step explanation:

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