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RideAnS [48]
4 years ago
12

A spherical conductor with a 0.193 m radius is initially uncharged. How many electrons should be removed from the sphere in orde

r for it to have an electrical potential of 7.10 kV at the surface?
Physics
1 answer:
kkurt [141]4 years ago
4 0

Answer:

The number of electrons removed is  N  = 9.513 *10^{11}

Explanation:

From hr question we are told that

    The radius is  r = 0.193 \ m

   The required electrical potential is V  =  7.10 \ kV  =  7.10 *10^{3} V

The total charge on the sphere  is mathematically evaluated as

           Q = \frac{Vr}{k}

where k is the coulombs constant with value k =9)*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.

substituting value

          Q = \frac{7.10 *10^3 * 0.193}{9*10^9}

          Q = 1.522*10^{-7} C

The number of electron removed is mathematically evaluated as

        N  =  \frac{Q}{e}

Where e is  the charge on one electron with value e = 1.6 *10^{-19} \ C

  substituting values  

      N  =  \frac{1.522 *10^{-7}}{1.60*10^{-19}}

      N  = 9.513 *10^{11}

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