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ololo11 [35]
3 years ago
9

Solve for the missing variable for each set. Showing ALL work through GUESS Method. Given, Unknown, Equation, Setup, Solve. 1. P

=?, M=20 kg, V=5 m/s 2. P= 3000 kg(m/s), M=?, V=75 m/s
Physics
1 answer:
Lelechka [254]3 years ago
5 0

Answer:

(1) P = 100 kg-m/s (2) M = 40 kg.

Explanation:

We need to solve the missing variable :

1. P=?, M=20 kg, V=5 m/s

If M is mass, V is velocity, then momentum P is given by :

P = MV

P = 20 kg × 5 m/s

P = 100 kg-m/s

(2) P= 3000 kg(m/s), M=?, V=75 m/s

M=\dfrac{P}{V}\\\\M=\dfrac{3000}{75}\\\\M = 40\ kg

Hence, P = 100 kg-m/s and M = 40 kg.

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If you hit another object with your vehicle, your _______ will be slowed or stopped by the force of impact caused by that object
BaLLatris [955]

Answer:

Speed

Explanation:

If a vehicle hit any other object then its speed will slow down or some time the vehicle will stop its depends on the force exerted by other object on the vehicle.

The change in speed of vehicle is due to momentum because momentum is always conserved. So to conserve the momentum the speed of the vehicle decreases because after hitting the overall mass is increases.

8 0
3 years ago
Read 2 more answers
Two small spheres spaced 20.0 cm apart have equal charge. How many excess electrons must be present on each sphere if the magnit
Snowcat [4.5K]

Answer:

894 electrons

Explanation:

The electrostatic force between the two charges is given by:

F=\frac{k q_1 q_2}{r^2}

where we have

F=4.57\cdot 10^{-21} N is the force

k is the Coulomb's constant

q1 = q2 =q is the magnitude of the charge on each sphere

r = 20.0 cm = 0.20 m is the distance between the two spheres

Substituting and solving for q, we find the charge on each sphere:

q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(4.57\cdot 10^{-21} N)(0.20 m)^2}{9\cdot 10^9 Nm^2C^{-2}}}=1.43\cdot 10^{-16} C

And since each electron has a charge of

e=1.6\cdot 10^{-19}C

the net charge on each sphere will be given by

q=Ne

where N is the number of excess electrons; solving for N,

N=\frac{q}{e}=\frac{1.43\cdot 10^{-16}C}{1.6\cdot 10^{-19}C}=894

7 0
4 years ago
What is the mass of a 2 kg object on the Earth and on the moon?
zubka84 [21]

Answer:

Same

Explanation:

Mass is the quantity of matter in a certain object.

WHEREVER you take a 2kg object, the mass will remain 2kg. All that changes is the Weight ..Weight the force which the centre of a Planet uses to pull everything towards itself.

On earth, it is 9.81 whereas on the Moon it is 1.6

7 0
3 years ago
The net force on an object moving with constant speed in circular motion is in which direction
ipn [44]

Answer:

the net force is the same direction as the acceleration

Explanation:

so toward the center of the circle about which the object is constantly moving.

7 0
3 years ago
A 13.0 g piece of Styrofoam carries a net charge of â5.40 μC and floats above the center of a large horizontal sheet of plastic
kati45 [8]

Answer:

σ =4.180×10^{-9} C/m^2

Explanation:

electric field due to non conducting sheet is

E=\frac{\sigma}{2\epsilon_0}

the force acting on the piece of Styrofoam

Eq= mg

⇒E= mg/q

now,

\frac{mg}{q} = \frac{\sigma}{2\epsilon_0}

⇒\sigma= \frac{2mg\epsilon_0}{q}

\sigma= \frac{2\times0.013\times9.81\times8.85\times10^{-12}}{5.40\times10^{-4}}

charge per unit area (in C/m2) on the plastic sheet σ =4.180×10^{-9} C/m^2

6 0
3 years ago
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