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ololo11 [35]
3 years ago
9

Solve for the missing variable for each set. Showing ALL work through GUESS Method. Given, Unknown, Equation, Setup, Solve. 1. P

=?, M=20 kg, V=5 m/s 2. P= 3000 kg(m/s), M=?, V=75 m/s
Physics
1 answer:
Lelechka [254]3 years ago
5 0

Answer:

(1) P = 100 kg-m/s (2) M = 40 kg.

Explanation:

We need to solve the missing variable :

1. P=?, M=20 kg, V=5 m/s

If M is mass, V is velocity, then momentum P is given by :

P = MV

P = 20 kg × 5 m/s

P = 100 kg-m/s

(2) P= 3000 kg(m/s), M=?, V=75 m/s

M=\dfrac{P}{V}\\\\M=\dfrac{3000}{75}\\\\M = 40\ kg

Hence, P = 100 kg-m/s and M = 40 kg.

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The mertric unit of electrical power is the _____. A. watt B.volt C.ampere D.ohm
sladkih [1.3K]

Answer:

A - Watt

Explanation:

Watt is the unit of electrical power in a metric system, expressed in terms of energy per second, equal to the work done at a rate of 1 joule per second is

power formula is P = V × I,

                                              where V is the voltage in a circuit

                                                      I is the current flowing through that circuit.

In the SI (metric) system, the units of power are watts.

5 0
3 years ago
A storm cloud has a charge of 0.055 C. Due to polarization, the top of a tree gains a charge of -0.006 C. The cloud moves to 98
Anastasy [175]

Answer:

F = 309.24 N

Explanation:

Given that,

Charge on a strom cloud, q₁ = 0.055 C

The charge gained by the top of a tree, q₂ = -0.006 C

The cloud moves to 98 meters above the tree.

We need to find the amount of force between the cloud and the tree. The electrical force between two charges is given by :

F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 0.055\times 0.006 }{(98)^2}\\\\F=309.24\ N

So, the force between the cloud and the tree is equal to 309.24 N.

5 0
3 years ago
A flag pole 18m high casts a shadow 9.6m long . Find the distance of top of pole from the far of end of Shadow. ​
puteri [66]

Answer:

{ \bf{pythogras \: theorem :}} \\   \\ { \tt{ =  \sqrt{ {9.6}^{2} +  {18}^{2}  } }} \\  = 20.4 \: cm

8 0
3 years ago
The frequency of the fundamental of the guitar string is 320 Hz. At what speed c do waves move along that string?
viktelen [127]

Complete question is The frequency of the fundamental of the guitar string is 320 Hz. At what speed c do waves move along that string?  wavelength is 40 cm.

Answer:

128 m/s  

Explanation:

In case where fundamental frequency is given, the speed with waves travel along the string can be calculated using the following formula:

v = f (2L) where L is the length of the string (L = λ/2)

⇒v= f λ

f = 320 Hz (given)

λ = 40 cm = 0.40 m

Substitute the values:

⇒ v = 320 Hz × 0.40 m=  128 m/s

7 0
3 years ago
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