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kherson [118]
3 years ago
11

Work is done on an object only if the force and displacement are __________?

Physics
1 answer:
miskamm [114]3 years ago
8 0
It’s either movement or work or that’s what a quizzie said
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16 V

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What is the order of the types of nuclear radiation from lowest to highest
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3 years ago
Physics Homework
katrin2010 [14]

Explanation:

a. Average speed = distance / time

= 100 m / 70 s

= 1.43 m/s

b. Average displacement = displacement / time

= 0 m / 70 s

= 0 m/s

Distance is the length of the path traveled.  Displacement is the difference between the final position and initial position.

4 0
4 years ago
If the 78.0 kg astronaut were in a spacecraft 6R from the center of the earth, what would the astronaut's weight be on earth? 76
den301095 [7]

(a) 764.4 N

The weight of the astronaut on Earth is given by:

F=mg

where

m is the astronaut's mass

g is the acceleration due to gravity

Here we have

m = 78.0 kg

g = 9.8 m/s^2 at the Earth's surface

So the weight of the astronaut is

F=(78.0)(9.8)=764.4 N

(b) 21.1 N

The spacecraft is located at a distance of

r=6R

from the center of Earth.

The acceleration due to gravity at a generic distance r from the Earth's center is

g=\frac{GM}{r^2}

where G is the gravitational constant and M is the Earth's mass.

We know that at a distance of r = R (at the Earth's surface) the value of g is 9.8 m/s^2, so we can write:

GM=9.8R^2 (1)

the acceleration due to gravity at r=6R instead will be

g'=\frac{GM}{(6R)^2}

And substituting (1) into this formula,

g'=\frac{9.8R^2}{36R^2}=0.27 m/s^2

So the weight of the astronaut at the spacecratf location is

F'=mg'=(78.0 kg)(0.27 m/s^2)=21.1 N

6 0
3 years ago
What is the test for whether or not a moving object is in equilibrium?
Sphinxa [80]

It is in equilibrium if its velocity is not changing.

3 0
3 years ago
Read 2 more answers
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