Question

PLEASE HELP !!!

Answer 1

Answer:

$x=0,4$.

Step-by-step explanation:

We have been given two functions.$f(x) = x^2-2x-4$ and $g(x) = 2x - 4$. We are asked to find the point, where both functions intersect.

To find the intersection point of both graphs, we will equate both equations as:

$x^2-2x-4=2x-4$

Combine like terms:

$x^2-2x-2x-4+4=2x-2x-4+4$

$x^2-4x=0$

Now, we will factor out x as:

$x(x-4)=0$

Using zero product property, we will get:

$x=0\text{ (or) }x-4=0$

$x=0\text{ (or) }x=4$

Therefore, the both graphs intersect at $x=0,4$.

Answer 2

x = 0 and x = 4

To find intersection equate them.

x² - 2x - 4 = 2x - 4

subtract 2x - 4 from both sides

x² - 4x = 0 → (take out common factor x)

x(x - 4 ) = 0 ⇒ x = 0 , x = 4